1
JEE Main 2019 (Online) 12th January Morning Slot
MCQ (Single Correct Answer)
+4
-1
If $$\lambda $$ be the ratio of the roots of the quadratic equation in x, 3m2x2 + m(m – 4)x + 2 = 0, then the least value of m for which $$\lambda + {1 \over \lambda } = 1,$$ is
A
$$ - 2 + \sqrt 2 $$
B
4$$-$$3$$\sqrt 2 $$
C
2 $$-$$ $$\sqrt 3 $$
D
4 $$-$$ 2$$\sqrt 3 $$
2
JEE Main 2019 (Online) 11th January Evening Slot
MCQ (Single Correct Answer)
+4
-1
Let $$\alpha $$ and $$\beta $$ be the roots of the quadratic equation x2 sin $$\theta $$ – x(sin $$\theta $$ cos $$\theta $$ + 1) + cos $$\theta $$ = 0 (0 < $$\theta $$ < 45o), and $$\alpha $$ < $$\beta $$. Then $$\sum\limits_{n = 0}^\infty {\left( {{\alpha ^n} + {{{{\left( { - 1} \right)}^n}} \over {{\beta ^n}}}} \right)} $$ is equal to :
A
$${1 \over {1 + \cos \theta }} + {1 \over {1 - \sin \theta }}$$
B
$${1 \over {1 - \cos \theta }} + {1 \over {1 + \sin \theta }}$$
C
$${1 \over {1 - \cos \theta }} - {1 \over {1 + \sin \theta }}$$
D
$${1 \over {1 + \cos \theta }} - {1 \over {1 - \sin \theta }}$$
3
JEE Main 2019 (Online) 11th January Morning Slot
MCQ (Single Correct Answer)
+4
-1
If one real root of the quadratic equation 81x2 + kx + 256 = 0 is cube of the other root, then a value of k is
A
$$-$$ 81
B
$$-$$ 300
C
100
D
144
4
JEE Main 2019 (Online) 10th January Evening Slot
MCQ (Single Correct Answer)
+4
-1
The value of $$\lambda $$ such that sum of the squares of the roots of the quadratic equation, x2 + (3 – $$\lambda $$)x + 2 = $$\lambda $$ has the least value is -
A
1
B
2
C
$${{15} \over 8}$$
D
$${4 \over 9}$$
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