1
JEE Main 2017 (Online) 8th April Morning Slot
+4
-1
Let p(x) be a quadratic polynomial such that p(0)=1. If p(x) leaves remainder 4 when divided by x$$-$$ 1 and it leaves remainder 6 when divided by x + 1; then :
A
p(2) = 11
B
p(2) = 19
C
p($$-$$ 2) = 19
D
p($$-$$ 2) = 11
2
JEE Main 2017 (Offline)
+4
-1
If for a positive integer n, the quadratic equation

$$x\left( {x + 1} \right) + \left( {x + 1} \right)\left( {x + 2} \right)$$$$+ .... + \left( {x + \overline {n - 1} } \right)\left( {x + n} \right)$$$$= 10n$$

has two consecutive integral solutions, then n is equal to :
A
9
B
10
C
11
D
12
3
JEE Main 2016 (Online) 10th April Morning Slot
+4
-1
If x is a solution of the equation, $$\sqrt {2x + 1}$$ $$- \sqrt {2x - 1} = 1,$$ $$\,\,\left( {x \ge {1 \over 2}} \right),$$ then $$\sqrt {4{x^2} - 1}$$ is equal to :
A
$${3 \over 4}$$
B
$${1 \over 2}$$
C
2
D
$$2\sqrt 2$$
4
JEE Main 2016 (Online) 9th April Morning Slot
+4
-1
If the equations x2 + bx−1 = 0 and x2 + x + b = 0 have a common root different from −1, then $$\left| b \right|$$ is equal to :
A
$$\sqrt 2$$
B
2
C
3
D
$$\sqrt 3$$
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