1
MCQ (Single Correct Answer)

### JEE Main 2017 (Online) 9th April Morning Slot

From a group of 10 men and 5 women, four member committees are to be formed each of which must contain at least one woman. Then the probability for these committees to have more women than men, is :
A
${{21} \over {220}}$
B
${{3} \over {11}}$
C
${{1} \over {11}}$
D
${{2} \over {23}}$
2
MCQ (Single Correct Answer)

### JEE Main 2017 (Online) 9th April Morning Slot

Let E and F be two independent events. The probability that both E and F happen is ${1 \over {12}}$ and the probability that neither E nor F happens is ${1 \over {2}}$, then a value of ${{P\left( E \right)} \over {P\left( F \right)}}$ is :
A
${4 \over 3}$
B
${3 \over 2}$
C
${1 \over 3}$
D
${5 \over 12}$
3
MCQ (Single Correct Answer)

### JEE Main 2018 (Offline)

A bag contains 4 red and 6 black balls. A ball is drawn at random from the bag, its colour is observed and this ball along with two additional balls of the same colour are returned to the bag. If now a ball is drawn at random from the bag, then the probability that this drawn ball is red, is :
A
${3 \over 4}$
B
${3 \over 10}$
C
${2 \over 5}$
D
${1 \over 5}$

## Explanation

If we follow path 1, then probability of getting 1st ball black $= {6 \over {10}}$ and probability of getting 2nd ball red when there is 4 R and 8 B balls = ${4 \over {12}}$.

So, the probability of getting 1st ball black and 2nd ball red = ${6 \over {10}} \times {4 \over {12}}$.

If we follow path 2, then the probability of getting 1st ball red $= {4 \over {10}}$ and probability of getting 2nd ball red when in the bag there is 6 red and 6 black balls = ${6 \over {12}}$

$\therefore\,\,\,$ Probability of getting 2nd ball as red

$= {6 \over {10}} \times {4 \over {12}} + {4 \over {10}} \times {6 \over {12}}$

$= {1 \over 5} + {1 \over 5}$

$= {2 \over 5}$
4
MCQ (Single Correct Answer)

### JEE Main 2018 (Online) 15th April Morning Slot

A box 'A' contains $2$ white, $3$ red and $2$ black balls. Another box 'B' contains $4$ white, $2$ red and $3$ black balls. If two balls are drawn at random, without eplacement, from a randomly selected box and one ball turns out to be white while the other ball turns out to be red, then the probability that both balls are drawn from box 'B' is :
A
${9 \over {16}}$
B
${7 \over {16}}$
C
${9 \over {32}}$
D
${7 \over {8}}$

## Explanation

Probability of drawing a white ball and then a red ball

from bag B is given by ${{{}^4{C_1} \times {}^2{C_1}} \over {{}^9{C_2}}}$ = ${2 \over 9}$

Probability of drawing a white ball and then a red ball

from bag A is given by ${{{}^2{C_1} \times {}^3{C_1}} \over {{}^7{C_2}}}$ = ${2 \over 7}$

Hence, the probability of drawing a white ball and then

a red ball from bag B = ${{{2 \over 9}} \over {{2 \over 7} + {2 \over 9}}}$ = ${{2 \times 7} \over {18 + 14}}$ = ${7 \over {16}}$

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