1
JEE Main 2019 (Online) 9th January Evening Slot
+4
-1
An urn contains 5 red and 2 green balls. A ball is drawn at random from the urn. If the drawn ball is green, then a red ball is added to the urn and if the drawn ball is red, then a green ball is added to the urn; the original ball is not returned to the urn. Now, a second ball is drawn at random from it. The probability that the second ball is red, is :
A
$${{21} \over {49}}$$
B
$${{27} \over {49}}$$
C
$${{26} \over {49}}$$
D
$${{32} \over {49}}$$
2
JEE Main 2019 (Online) 9th January Morning Slot
+4
-1
Out of Syllabus
Two cards are drawn successively with replacement from a well-shuffled deck of 52 cards. Let X denote the random variable of number of aces obtained in the two drawn cards. Then P(X = 1) + P (X = 2) equals :
A
$$25 \over 169$$
B
$$49\over 169$$
C
$$24 \over 169$$
D
$$52 \over 169$$
3
JEE Main 2018 (Online) 16th April Morning Slot
+4
-1
Let A, B and C be three events, which are pair-wise independent and $$\overrightarrow E$$ denotes the completement of an event E. If $$P\left( {A \cap B \cap C} \right) = 0$$ and $$P\left( C \right) > 0,$$ then $$P\left[ {\left( {\overline A \cap \overline B } \right)\left| C \right.} \right]$$ is equal to :
A
$$P\left( {\overline A } \right) - P\left( B \right)$$
B
$$P\left( A \right) + P\left( {\overline B } \right)$$
C
$$P\left( {\overline A } \right) - P\left( {\overline B } \right)$$
D
$$P\left( {\overline A } \right) + P\left( {\overline B } \right)$$
4
JEE Main 2018 (Online) 16th April Morning Slot
+4
-1
Two different families A and B are blessed with equal numbe of children. There are 3 tickets to be distributed amongst the children of these families so that no child gets more than one ticket. If the probability that all the tickets go to the children of the family B is $${1 \over {12}},$$ then the number of children in each family is :
A
3
B
4
C
5
D
6
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