1
AIEEE 2010
+4
-1
Four numbers are chosen at random (without replacement) from the set $$\left\{ {1,2,3,....20} \right\}.$$

Statement - 1: The probability that the chosen numbers when arranged in some order will form an AP is $${1 \over {85}}.$$

Statement - 2: If the four chosen numbers form an AP, then the set of all possible values of common difference is $$\left( { \pm 1, \pm 2, \pm 3, \pm 4, \pm 5} \right).$$

A
Statement - 1 is true, Statement - 2 is true; Statement - 2 is not a correct explanation for Statement - 1.
B
Statement - 1 is true, Statement - 2 is false.
C
Statement - 1 is false, Statement -2 is true.
D
Statement - 1 is true, Statement - 2 is true; Statement - 2 is a correct explanation for Statement - 1.
2
AIEEE 2010
+4
-1
An urn contains nine balls of which three are red, four are blue and two are green. Three balls are drawn at random without replacement from the urn. The probability that the three balls have different colours is :
A
$${2 \over 7}$$
B
$${1 \over 21}$$
C
$${1 \over 23}$$
D
$${1 \over 3}$$
3
AIEEE 2009
+4
-1
Out of Syllabus
In a binomial distribution $$B\left( {n,p = {1 \over 4}} \right),$$ if the probability of at least one success is greater than or equal to $${9 \over {10}},$$ then $$n$$ is greater than :
A
$${1 \over {\log _{10}^4 + \log _{10}^3}}$$
B
$${9 \over {\log _{10}^4 - \log _{10}^3}}$$
C
$${4 \over {\log _{10}^4 - \log _{10}^3}}$$
D
$${1 \over {\log _{10}^4 - \log _{10}^3}}$$
4
AIEEE 2009
+4
-1
One ticket is selected at random from $$50$$ tickets numbered $$00, 01, 02, ...., 49.$$ Then the probability that the sum of the digits on the selected ticket is $$8$$, given that the product of these digits is zer, equals :
A
$${1 \over 7}$$
B
$${5 \over 14}$$
C
$${1 \over 50}$$
D
$${1 \over 14}$$
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