1
AIEEE 2009
+4
-1
Out of Syllabus
In a binomial distribution $$B\left( {n,p = {1 \over 4}} \right),$$ if the probability of at least one success is greater than or equal to $${9 \over {10}},$$ then $$n$$ is greater than :
A
$${1 \over {\log _{10}^4 + \log _{10}^3}}$$
B
$${9 \over {\log _{10}^4 - \log _{10}^3}}$$
C
$${4 \over {\log _{10}^4 - \log _{10}^3}}$$
D
$${1 \over {\log _{10}^4 - \log _{10}^3}}$$
2
AIEEE 2008
+4
-1
A die is thrown. Let $$A$$ be the event that the number obtained is greater than $$3.$$ Let $$B$$ be the event that the number obtained is less than $$5.$$ Then $$P\left( {A \cup B} \right)$$ is :
A
$${3 \over 5}$$
B
$$0$$
C
$$1$$
D
$${2 \over 5}$$
3
AIEEE 2008
+4
-1
It is given that the events $$A$$ and $$B$$ are such that
$$P\left( A \right) = {1 \over 4},P\left( {A|B} \right) = {1 \over 2}$$ and $$P\left( {B|A} \right) = {2 \over 3}.$$ Then $$P(B)$$ is :
A
$${1 \over 6}$$
B
$${1 \over 3}$$
C
$${2 \over 3}$$
D
$${1 \over 2}$$
4
AIEEE 2007
+4
-1
Two aeroplanes $${\rm I}$$ and $${\rm I}$$$${\rm I}$$ bomb a target in succession. The probabilities of $${\rm I}$$ and $${\rm I}$$$${\rm I}$$ scoring a hit correctly are $$0.3$$ and $$0.2,$$ respectively. The second plane will bomb only if the first misses the target. The probability that the target is hit by the second plane is :
A
$$0.2$$
B
$$0.7$$
C
$$0.06$$
D
0.32
EXAM MAP
Medical
NEET