The number of real solutions of the equation $${x^2} - 3\left| x \right| + 2 = 0$$ is

Product of real roots of equation $${t^2}{x^2} + \left| x \right| + 9 = 0$$

Difference between the corresponding roots of $${x^2} + ax + b = 0$$ and $${x^2} + bx + a = 0$$ is same and $$a \ne b,$$ then

If $$p$$ and $$q$$ are the roots of the equation $${x^2} + px + q = 0,$$ then