1
AIEEE 2005
+4
-1
A random variable $$X$$ has Poisson distribution with mean $$2$$.
Then $$P\left( {X > 1.5} \right)$$ equals :
A
$${2 \over {{e^2}}}$$
B
$$0$$
C
$$1 - {3 \over {{e^2}}}$$
D
$${3 \over {{e^2}}}$$
2
AIEEE 2005
+4
-1
Let $$A$$ and $$B$$ two events such that $$P\left( {\overline {A \cup B} } \right) = {1 \over 6},$$ $$P\left( {A \cap B} \right) = {1 \over 4}$$ and $$P\left( {\overline A } \right) = {1 \over 4},$$ where $${\overline A }$$ stands for complement of event $$A$$. Then events $$A$$ and $$B$$ are :
A
equally likely and mutually exclusive
B
equally likely but not independent
C
independent but not equally likely
D
mutually exclusive and independent
3
AIEEE 2004
+4
-1
Out of Syllabus
The mean and the variance of a binomial distribution are $$4$$ and $$2$$ respectively. Then the probability of $$2$$ successes is :
A
$${28 \over 256}$$
B
$${219 \over 256}$$
C
$${128 \over 256}$$
D
$${37 \over 256}$$
4
AIEEE 2004
+4
-1
The probability that $$A$$ speaks truth is $${4 \over 5},$$ while the probability for $$B$$ is $${3 \over 4}.$$ The probability that they contradict each other when asked to speak on a fact is :
A
$${4 \over 5}$$
B
$${1 \over 5}$$
C
$${7 \over 20}$$
D
$${3 \over 20}$$
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