If $${\left( {{{1 + i} \over {1 - i}}} \right)^x} = 1$$ then :

If $$\left| {z - 4} \right| < \left| {z - 2} \right|$$, its solution is given by :

z and w are two nonzero complex numbers such that $$\,\left| z \right| = \left| w \right|$$ and Arg z + Arg w =$$\pi $$ then z equals

The locus of the centre of a circle which touches the circle $$\left| {z - {z_1}} \right| = a$$ and$$\left| {z - {z_2}} \right| = b\,$$ externally

($$z,\,{z_1}\,\& \,{z_2}\,$$ are complex numbers) will be :