1
AIEEE 2010
+4
-1
An urn contains nine balls of which three are red, four are blue and two are green. Three balls are drawn at random without replacement from the urn. The probability that the three balls have different colours is :
A
$${2 \over 7}$$
B
$${1 \over 21}$$
C
$${1 \over 23}$$
D
$${1 \over 3}$$
2
AIEEE 2009
+4
-1
One ticket is selected at random from $$50$$ tickets numbered $$00, 01, 02, ...., 49.$$ Then the probability that the sum of the digits on the selected ticket is $$8$$, given that the product of these digits is zer, equals :
A
$${1 \over 7}$$
B
$${5 \over 14}$$
C
$${1 \over 50}$$
D
$${1 \over 14}$$
3
AIEEE 2009
+4
-1
Out of Syllabus
In a binomial distribution $$B\left( {n,p = {1 \over 4}} \right),$$ if the probability of at least one success is greater than or equal to $${9 \over {10}},$$ then $$n$$ is greater than :
A
$${1 \over {\log _{10}^4 + \log _{10}^3}}$$
B
$${9 \over {\log _{10}^4 - \log _{10}^3}}$$
C
$${4 \over {\log _{10}^4 - \log _{10}^3}}$$
D
$${1 \over {\log _{10}^4 - \log _{10}^3}}$$
4
AIEEE 2008
+4
-1
A die is thrown. Let $$A$$ be the event that the number obtained is greater than $$3.$$ Let $$B$$ be the event that the number obtained is less than $$5.$$ Then $$P\left( {A \cup B} \right)$$ is :
A
$${3 \over 5}$$
B
$$0$$
C
$$1$$
D
$${2 \over 5}$$
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