1
JEE Main 2013 (Offline)
MCQ (Single Correct Answer)
+4
-1
Out of Syllabus
The sum of first 20 terms of the sequence 0.7, 0.77, 0.777,........,is
A
$${7 \over {81}}\left( {179 - {{10}^{ - 20}}} \right)$$
B
$$\,{7 \over 9}\left( {99 - {{10}^{ - 20}}} \right)$$
C
$${7 \over {81}}\left( {179 + {{10}^{ - 20}}} \right)$$
D
$${7 \over 9}\left( {99 + {{10}^{ - 20}}} \right)$$
2
AIEEE 2012
MCQ (Single Correct Answer)
+4
-1
Out of Syllabus

Statement-1: The sum of the series 1 + (1 + 2 + 4) + (4 + 6 + 9) + (9 + 12 + 16) +.....+ (361 + 380 + 400) is 8000.

Statement-2: $$\sum\limits_{k = 1}^n {\left( {{k^3} - {{(k - 1)}^3}} \right)} = {n^3}$$, for any natural number n.

A
Statement-1 is false, Statement-2 is true.
B
Statement-1 is true, Statement-2 is true; Statement-2 is a correct explanation for Statement-1.
C
Statement-1 is true, Statement-2 is true; Statement-2 is not a correct explanation for Statement-1.
D
Statement-1 is true, Statement-2 is false.
3
AIEEE 2011
MCQ (Single Correct Answer)
+4
-1
A man saves ₹ 200 in each of the first three months of his service. In each of the subsequent months his saving increases by ₹ 40 more than the saving of immediately previous month. His total saving from the start of service will be ₹ 11040 after
A
19 months
B
20 months
C
21 months
D
18 months
4
AIEEE 2010
MCQ (Single Correct Answer)
+4
-1
A person is to count 4500 currency notes. Let $${a_n}$$ denote the number of notes he counts in the $${n^{th}}$$ minute. If $${a_1}$$ = $${a_2}$$ = ....= $${a_{10}}$$= 150 and $${a_{10}}$$, $${a_{11}}$$,.... are in an AP with common difference - 2, then the time taken by him to count all notes is
A
34 minutes
B
125 minutes
C
135 minutes
D
24 minutes
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