1
JEE Main 2021 (Online) 18th March Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language
Let S1 be the sum of first 2n terms of an arithmetic progression. Let S2 be the sum of first 4n terms of the same arithmetic progression. If (S2 $$-$$ S1) is 1000, then the sum of the first 6n terms of the arithmetic progression is equal to :
A
7000
B
1000
C
3000
D
5000
2
JEE Main 2021 (Online) 18th March Morning Shift
MCQ (Single Correct Answer)
+4
-1
Out of Syllabus
Change Language
If $$\alpha$$, $$\beta$$ are natural numbers such that
100$$\alpha$$ $$-$$ 199$$\beta$$ = (100)(100) + (99)(101) + (98)(102) + ...... + (1)(199), then the slope of the line passing through ($$\alpha$$, $$\beta$$) and origin is :
A
540
B
550
C
530
D
510
3
JEE Main 2021 (Online) 18th March Morning Shift
MCQ (Single Correct Answer)
+4
-1
Out of Syllabus
Change Language
$${1 \over {{3^2} - 1}} + {1 \over {{5^2} - 1}} + {1 \over {{7^2} - 1}} + .... + {1 \over {{{(201)}^2} - 1}}$$ is equal to
A
$${{101} \over {404}}$$
B
$${{25} \over {101}}$$
C
$${{101} \over {408}}$$
D
$${{99} \over {400}}$$
4
JEE Main 2021 (Online) 26th February Evening Shift
MCQ (Single Correct Answer)
+4
-1
Out of Syllabus
Change Language
The sum of the series

$$\sum\limits_{n = 1}^\infty {{{{n^2} + 6n + 10} \over {(2n + 1)!}}} $$ is equal to :
A
$${{41} \over 8}e + {{19} \over 8}{e^{ - 1}} - 10$$
B
$${{41} \over 8}e - {{19} \over 8}{e^{ - 1}} - 10$$
C
$${{41} \over 8}e + {{19} \over 8}{e^{ - 1}} + 10$$
D
$$ - {{41} \over 8}e + {{19} \over 8}{e^{ - 1}} - 10$$
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