The negation of the Boolean expression x $$ \leftrightarrow $$ ~ y is equivalent to :

Contrapositive of the statement :
‘If a function f is differentiable at a, then it is also continuous at a’, is:

Given the following two statements:

$$\left( {{S_1}} \right):\left( {q \vee p} \right) \to \left( {p \leftrightarrow \sim q} \right)$$ is a tautology

$$\left( {{S_2}} \right): \,\,\sim q \wedge \left( { \sim p \leftrightarrow q} \right)$$ is a fallacy. Then:

Let p, q, r be three statements such that the truth value of
(p $$ \wedge $$ q) $$ \to $$ ($$ \sim $$q $$ \vee $$ r) is F. Then the truth values of p, q, r are respectively :