This chapter is currently out of syllabus
1
AIEEE 2009
+4
-1
Out of Syllabus
Statement-1 : $$\sim \left( {p \leftrightarrow \sim q} \right)$$ is equivalent to $${p \leftrightarrow q}$$.
Statement-2 : $$\sim \left( {p \leftrightarrow \sim q} \right)$$ is a tautology.
A
Statement-1 is true, Statement-2 is true; Statement-2 is a correct explanation for Statement-1
B
Statement-1 is true, Statement-2 is true; Statement-2 is not a correct explanation for Statement-1
C
Statement-1 is true, Statement-2 is false
D
Statement-1 is false, Statement-2 is true
2
AIEEE 2008
+4
-1
Out of Syllabus
Let p be the statement “x is an irrational number”, q be the statement “y is a transcendental number”, and r be the statement “x is a rational number iff y is a transcendental number”.

Statement –1: r is equivalent to either q or p.

Statement –2: r is equivalent to $$\sim \left( {p \leftrightarrow \sim q} \right)$$
A
Statement − 1 is false, Statement − 2 is false
B
Statement −1 is false, Statement −2 is true
C
Statement −1 is true, Statement −2 is true, Statement −2 is a correct explanation for Statement −1
D
Statement −1 is true, Statement −2 is true; Statement −2 is not a correct explanation for Statement −1
3
AIEEE 2008
+4
-1
Out of Syllabus
The statement $$p \to \left( {q \to p} \right)$$ is equivalent to
A
$$p \to \left( {p \leftrightarrow q} \right)$$
B
$$p \to \left( {p \to q} \right)$$
C
$$p \to \left( {p \vee q} \right)$$
D
$$p \to \left( {p \wedge q} \right)$$
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