The negation of the statement $$(p \vee q) \wedge (q \vee ( \sim r))$$ is :

The negation of $$(p \wedge(\sim q)) \vee(\sim p)$$ is equivalent to :

Negation of $$(p \Rightarrow q) \Rightarrow(q \Rightarrow p)$$ is :

Among the statements

(S1) : $$(p \Rightarrow q) \vee((\sim p) \wedge q)$$ is a tautology

(S2) : $$(q \Rightarrow p) \Rightarrow((\sim p) \wedge q)$$ is a contradiction