JEE Main 2021 (Online) 17th March Evening Shift | Mathematical Reasoning Question 63 | Mathematics

If the Boolean expression (p $$ \Rightarrow $$ q) $$ \Leftrightarrow $$ (q * ($$ \sim $$p) is a tautology, then the boolean expression (p * ($$ \sim $$q)) is equivalent to :

q $$ \Rightarrow $$ p

p $$ \Rightarrow $$ q

p $$ \Rightarrow $$ $$ \sim $$ q

$$ \sim $$q $$ \Rightarrow $$ p

JEE Main 2021 (Online) 16th March Morning Shift

MCQ (Single Correct Answer)

-1

Out of Syllabus

Which of the following Boolean expression is a tautology?

(p $$ \wedge $$ q) $$ \vee $$ (p $$ \to $$ q)

(p $$ \wedge $$ q) $$ \vee $$ (p $$\vee$$ q)

(p $$ \wedge $$ q) $$ \to $$ (p $$ \to $$ q)

(p $$ \wedge $$ q) $$ \wedge $$ (p $$ \to $$ q)

JEE Main 2021 (Online) 26th February Evening Shift

MCQ (Single Correct Answer)

-1

Out of Syllabus

Let F₁(A, B, C) = (A $$ \wedge $$ $$ \sim $$ B) $$ \vee $$ [$$\sim$$C $$\wedge$$ (A $$\vee$$ B)] $$\vee$$ $$\sim$$ A and
F₂(A, B) = (A $$\vee$$ B) $$\vee$$ (B $$ \to $$ $$\sim$$A) be two logical expressions. Then :

Both F₁ and F₂ are not tautologies

F₁ and F₂ both are tautologies

F₁ is not a tautology but F₂ is a tautology

F₁ is a tautology but F₂ is not a tautology

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