This chapter is currently out of syllabus
1
JEE Main 2020 (Online) 4th September Evening Slot
+4
-1
Out of Syllabus
Contrapositive of the statement :
‘If a function f is differentiable at a, then it is also continuous at a’, is:
A
If a function f is continuous at a, then it is not differentiable at a.
B
If a function f is not continuous at a, then it is differentiable at a.
C
If a function f is not continuous at a, then it is not differentiable at a.
D
If a function f is continuous at a, then it is differentiable at a.
2
JEE Main 2020 (Online) 4th September Morning Slot
+4
-1
Out of Syllabus
Given the following two statements:

$$\left( {{S_1}} \right):\left( {q \vee p} \right) \to \left( {p \leftrightarrow \sim q} \right)$$ is a tautology

$$\left( {{S_2}} \right): \,\,\sim q \wedge \left( { \sim p \leftrightarrow q} \right)$$ is a fallacy. Then:
A
both (S1) and (S2) are not correct
B
only (S1) is correct
C
only (S2) is correct
D
both (S1) and (S2) are correct
3
JEE Main 2020 (Online) 3rd September Evening Slot
+4
-1
Out of Syllabus
Let p, q, r be three statements such that the truth value of
(p $$\wedge$$ q) $$\to$$ ($$\sim$$q $$\vee$$ r) is F. Then the truth values of p, q, r are respectively :
A
T, F, T
B
F, T, F
C
T, T, T
D
T, T, F
4
JEE Main 2020 (Online) 3rd September Morning Slot
+4
-1
Out of Syllabus
The proposition p $$\to$$ ~ (p $$\wedge$$ ~q) is equivalent to :
A
($$\sim$$p) $$\vee$$ q
B
q
C
($$\sim$$p) $$\wedge$$ q
D
($$\sim$$p) $$\vee$$ ($$\sim$$q)
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