1
JEE Main 2020 (Online) 8th January Morning Slot
+4
-1
Let the line y = mx and the ellipse 2x2 + y2 = 1 intersect at a ponit P in the first quadrant. If the normal to this ellipse at P meets the co-ordinate axes at $$\left( { - {1 \over {3\sqrt 2 }},0} \right)$$ and (0, $$\beta$$), then $$\beta$$ is equal to
A
$${{\sqrt 2 } \over 3}$$
B
$${2 \over 3}$$
C
$${{2\sqrt 2 } \over 3}$$
D
$${2 \over {\sqrt 3 }}$$
2
JEE Main 2020 (Online) 8th January Morning Slot
+4
-1
The locus of a point which divides the line segment joining the point (0, –1) and a point on the parabola, x2 = 4y, internally in the ratio 1 : 2, is :
A
9x2 – 3y = 2
B
4x2 – 3y = 2
C
x2 – 3y = 2
D
9x2 – 12y = 8
3
JEE Main 2020 (Online) 7th January Evening Slot
+4
-1
If 3x + 4y = 12$$\sqrt 2$$ is a tangent to the ellipse
$${{{x^2}} \over {{a^2}}} + {{{y^2}} \over 9} = 1$$ for some $$a$$ $$\in$$ R, then the distance between the foci of the ellipse is :
A
$$2\sqrt 5$$
B
$$2\sqrt 7$$
C
4
D
$$2\sqrt 2$$
4
JEE Main 2020 (Online) 7th January Morning Slot
+4
-1
If y = mx + 4 is a tangent to both the parabolas, y2 = 4x and x2 = 2by, then b is equal to:
A
-128
B
128
C
-64
D
-32
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