1
JEE Main 2020 (Online) 6th September Evening Slot
+4
-1
Out of Syllabus
If the normal at an end of a latus rectum of an ellipse passes through an extremity of the minor axis, then the eccentricity e of the ellipse satisfies :
A
e4 + 2e2 – 1 = 0
B
e4 + e2 – 1 = 0
C
e2 + 2e – 1 = 0
D
e2 + e – 1 = 0
2
JEE Main 2020 (Online) 6th September Morning Slot
+4
-1
Out of Syllabus
Which of the following points lies on the locus of the foot of perpedicular drawn upon any tangent to the ellipse,
$${{{x^2}} \over 4} + {{{y^2}} \over 2} = 1$$
from any of its foci?
A
$$\left( { - 1,\sqrt 3 } \right)$$
B
$$\left( { - 2,\sqrt 3 } \right)$$
C
$$\left( { - 1,\sqrt 2 } \right)$$
D
$$\left( {1,2 } \right)$$
3
JEE Main 2020 (Online) 5th September Morning Slot
+4
-1
If the co-ordinates of two points A and B
are $$\left( {\sqrt 7 ,0} \right)$$ and $$\left( { - \sqrt 7 ,0} \right)$$ respectively and
P is any point on the conic, 9x2 + 16y2 = 144, then PA + PB is equal to :
A
8
B
9
C
16
D
6
4
JEE Main 2020 (Online) 4th September Evening Slot
+4
-1
Out of Syllabus
Let x = 4 be a directrix to an ellipse whose centre is at the origin and its eccentricity is $${1 \over 2}$$. If P(1, $$\beta$$), $$\beta$$ > 0 is a point on this ellipse, then the equation of the normal to it at P is :
A
4x – 3y = 2
B
8x – 2y = 5
C
7x – 4y = 1
D
4x – 2y = 1
EXAM MAP
Medical
NEET