AIEEE 2011 | Ellipse Question 97 | Mathematics

The ellipse $${x^2} + 4{y^2} = 4$$ is inscribed in a rectangle aligned with the coordinate axex, which in turn is inscribed in another ellipse that passes through the point $$(4,0)$$. Then the equation of the ellipse is :

$${x^2} + 12{y^2} = 16$$

$$4{x^2} + 48{y^2} = 48$$

$$4{x^2} + 64{y^2} = 48$$

$${x^2} + 16{y^2} = 16$$

AIEEE 2008

MCQ (Single Correct Answer)

-1

A focus of an ellipse is at the origin. The directrix is the line $$x=4$$ and the eccentricity is $${{1 \over 2}}$$. Then the length of the semi-major axis is :

$${{8 \over 3}}$$

$${{2 \over 3}}$$

$${{4 \over 3}}$$

$${{5 \over 3}}$$

AIEEE 2006

MCQ (Single Correct Answer)

-1

In the ellipse, the distance between its foci is $$6$$ and minor axis is $$8$$. Then its eccentricity is :

$${3 \over 5}$$

$${1 \over 2}$$

$${4 \over 5}$$

$${1 \over {\sqrt 5 }}$$