1
JEE Main 2019 (Online) 10th April Evening Slot
+4
-1
Let a1, a2, a3,......be an A.P. with a6 = 2. Then the common difference of this A.P., which maximises the product a1a4a5, is :
A
$${3 \over 2}$$
B
$${6 \over 5}$$
C
$${8 \over 5}$$
D
$${2 \over 3}$$
2
JEE Main 2019 (Online) 10th April Morning Slot
+4
-1
Out of Syllabus
The sum
$${{3 \times {1^3}} \over {{1^3}}} + {{5 \times ({1^3} + {2^3})} \over {{1^2} + {2^2}}} + {{7 \times \left( {{1^3} + {2^3} + {3^3}} \right)} \over {{1^2} + {2^2} + {3^2}}} + .....$$ upto 10 terms is:
A
600
B
660
C
680
D
620
3
JEE Main 2019 (Online) 10th April Morning Slot
+4
-1
If a1, a2, a3, ............... an are in A.P. and a1 + a4 + a7 + ........... + a16 = 114, then a1 + a6 + a11 + a16 is equal to :
A
38
B
98
C
76
D
64
4
JEE Main 2019 (Online) 9th April Evening Slot
+4
-1
Out of Syllabus
Some identical balls are arranged in rows to form an equilateral triangle. The first row consists of one ball, the second row consists of two balls and so on. If 99 more identical balls are addded to the total number of balls used in forming the equilaterial triangle, then all these balls can be arranged in a square whose each side contains exactly 2 balls less than the number of balls each side of the triangle contains. Then the number of balls used to form the equilateral triangle is :-
A
262
B
190
C
157
D
225
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