1
JEE Main 2020 (Online) 2nd September Morning Slot
MCQ (Single Correct Answer)
+4
-1
The domain of the function
f(x) = $${\sin ^{ - 1}}\left( {{{\left| x \right| + 5} \over {{x^2} + 1}}} \right)$$ is (– $$\infty $$, -a]$$ \cup $$[a, $$\infty $$). Then a is equal to :
A
$${{\sqrt {17} - 1} \over 2}$$
B
$${{1 + \sqrt {17} } \over 2}$$
C
$${{\sqrt {17} } \over 2} + 1$$
D
$${{\sqrt {17} } \over 2}$$
2
JEE Main 2019 (Online) 12th April Morning Slot
MCQ (Single Correct Answer)
+4
-1
The value of $${\sin ^{ - 1}}\left( {{{12} \over {13}}} \right) - {\sin ^{ - 1}}\left( {{3 \over 5}} \right)$$ is equal to :
A
$$\pi - {\sin ^{ - 1}}\left( {{{63} \over {65}}} \right)$$
B
$${\pi \over 2} - {\sin ^{ - 1}}\left( {{{56} \over {65}}} \right)$$
C
$${\pi \over 2} - {\cos ^{ - 1}}\left( {{9 \over {65}}} \right)$$
D
$$\pi - {\cos ^{ - 1}}\left( {{{33} \over {65}}} \right)$$
3
JEE Main 2019 (Online) 10th April Evening Slot
MCQ (Single Correct Answer)
+4
-1
If $${\cos ^{ - 1}}x - {\cos ^{ - 1}}{y \over 2} = \alpha $$,where –1 $$ \le $$ x $$ \le $$ 1, – 2 $$ \le $$ y $$ \le $$ 2, x $$ \le $$ $${y \over 2}$$ , then for all x, y, 4x2 – 4xy cos $$\alpha $$ + y2 is equal to :
A
4 sin2 $$\alpha $$
B
2 sin2 $$\alpha $$
C
4 sin2 $$\alpha $$ - 2x2y2
D
4 cos2 $$\alpha $$ + 2x2y2
4
JEE Main 2019 (Online) 8th April Morning Slot
MCQ (Single Correct Answer)
+4
-1
If $$\alpha = {\cos ^{ - 1}}\left( {{3 \over 5}} \right)$$, $$\beta = {\tan ^{ - 1}}\left( {{1 \over 3}} \right)$$ where $$0 < \alpha ,\beta < {\pi \over 2}$$ , then $$\alpha $$ - $$\beta $$ is equal to :
A
$${\tan ^{ - 1}}\left( {{9 \over {14 }}} \right)$$
B
$${\sin ^{ - 1}}\left( {{9 \over {5\sqrt {10} }}} \right)$$
C
$${\cos ^{ - 1}}\left( {{9 \over {5\sqrt {10} }}} \right)$$
D
$${\tan ^{ - 1}}\left( {{9 \over {5\sqrt {10} }}} \right)$$
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