1
JEE Main 2019 (Online) 9th January Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
If  x = sin$$-$$1(sin10) and y = cos$$-$$1(cos10), then y $$-$$ x is equal to :
A
0
B
10
C
7$$\pi $$
D
$$\pi $$
2
JEE Main 2019 (Online) 9th January Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
If $${\cos ^{ - 1}}\left( {{2 \over {3x}}} \right) + {\cos ^{ - 1}}\left( {{3 \over {4x}}} \right) = {\pi \over 2}$$ (x > $$3 \over 4$$), then x is equal to :
A
$${{\sqrt {145} } \over {10}}$$
B
$${{\sqrt {145} } \over {11}}$$
C
$${{\sqrt {145} } \over {12}}$$
D
$${{\sqrt {146} } \over {12}}$$
3
JEE Main 2017 (Online) 9th April Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
A value of x satisfying the equation sin[cot−1 (1+ x)] = cos [tan−1 x], is :
A
$$ - {1 \over 2}$$
B
$$-$$ 1
C
0
D
$$ {1 \over 2}$$
4
JEE Main 2017 (Online) 8th April Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
The value of tan-1 $$\left[ {{{\sqrt {1 + {x^2}} + \sqrt {1 - {x^2}} } \over {\sqrt {1 + {x^2}} - \sqrt {1 - {x^2}} }}} \right],$$ $$\left| x \right| < {1 \over 2},x \ne 0,$$ is equal to :
A
$${\pi \over 4} + {1 \over 2}{\cos ^{ - 1}}\,{x^2}$$
B
$${\pi \over 4} + {\cos ^{ - 1}}\,{x^2}$$
C
$${\pi \over 4} - {1 \over 2}{\cos ^{ - 1}}\,{x^2}$$
D
$${\pi \over 4} - {\cos ^{ - 1}}\,{x^2}$$
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