1
JEE Main 2020 (Online) 3rd September Morning Slot
+4
-1
2$$\pi$$ - $$\left( {{{\sin }^{ - 1}}{4 \over 5} + {{\sin }^{ - 1}}{5 \over {13}} + {{\sin }^{ - 1}}{{16} \over {65}}} \right)$$ is equal to :
A
$${{7\pi } \over 4}$$
B
$${{5\pi } \over 4}$$
C
$${{3\pi } \over 2}$$
D
$${\pi \over 2}$$
2
JEE Main 2020 (Online) 2nd September Morning Slot
+4
-1
The domain of the function
f(x) = $${\sin ^{ - 1}}\left( {{{\left| x \right| + 5} \over {{x^2} + 1}}} \right)$$ is (– $$\infty$$, -a]$$\cup$$[a, $$\infty$$). Then a is equal to :
A
$${{\sqrt {17} - 1} \over 2}$$
B
$${{1 + \sqrt {17} } \over 2}$$
C
$${{\sqrt {17} } \over 2} + 1$$
D
$${{\sqrt {17} } \over 2}$$
3
JEE Main 2019 (Online) 12th April Morning Slot
+4
-1
The value of $${\sin ^{ - 1}}\left( {{{12} \over {13}}} \right) - {\sin ^{ - 1}}\left( {{3 \over 5}} \right)$$ is equal to :
A
$$\pi - {\sin ^{ - 1}}\left( {{{63} \over {65}}} \right)$$
B
$${\pi \over 2} - {\sin ^{ - 1}}\left( {{{56} \over {65}}} \right)$$
C
$${\pi \over 2} - {\cos ^{ - 1}}\left( {{9 \over {65}}} \right)$$
D
$$\pi - {\cos ^{ - 1}}\left( {{{33} \over {65}}} \right)$$
4
JEE Main 2019 (Online) 10th April Evening Slot
+4
-1
If $${\cos ^{ - 1}}x - {\cos ^{ - 1}}{y \over 2} = \alpha$$,where –1 $$\le$$ x $$\le$$ 1, – 2 $$\le$$ y $$\le$$ 2, x $$\le$$ $${y \over 2}$$ , then for all x, y, 4x2 – 4xy cos $$\alpha$$ + y2 is equal to :
A
4 sin2 $$\alpha$$
B
2 sin2 $$\alpha$$
C
4 sin2 $$\alpha$$ - 2x2y2
D
4 cos2 $$\alpha$$ + 2x2y2
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