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AIEEE 2002
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-1
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$${\cot ^{ - 1}}\left( {\sqrt {\cos \alpha } } \right) - {\tan ^{ - 1}}\left( {\sqrt {\cos \alpha } } \right) = x,$$ then sin x is equal to :
A
$${\tan ^2}\left( {{\alpha \over 2}} \right)$$
B
$${\cot ^2}\left( {{\alpha \over 2}} \right)$$
C
$$\tan \alpha $$
D
$$cot\left( {{\alpha \over 2}} \right)$$
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