1
JEE Main 2019 (Online) 9th April Morning Slot
+4
-1
Let $$\sum\limits_{k = 1}^{10} {f(a + k) = 16\left( {{2^{10}} - 1} \right)}$$ where the function ƒ satisfies
ƒ(x + y) = ƒ(x)ƒ(y) for all natural numbers x, y and ƒ(1) = 2. then the natural number 'a' is
A
2
B
16
C
4
D
3
2
JEE Main 2019 (Online) 9th April Morning Slot
+4
-1
If the function ƒ : R – {1, –1} $$\to$$ A defined by
ƒ(x) = $${{{x^2}} \over {1 - {x^2}}}$$ , is surjective, then A is equal to
A
R – (–1, 0)
B
R – {–1}
C
R – [–1, 0)
D
[0, $$\infty$$)
3
JEE Main 2019 (Online) 8th April Evening Slot
+4
-1
Let ƒ(x) = ax (a > 0) be written as
ƒ(x) = ƒ1 (x) + ƒ2 (x), where ƒ1 (x) is an even function of ƒ2 (x) is an odd function.
Then ƒ1 (x + y) + ƒ1 (x – y) equals
A
1 (x)ƒ1 (y)
B
1 (x + y)ƒ1 (x – y)
C
1 (x)ƒ2 (y)
D
1 (x + y)ƒ2 (x – y)
4
JEE Main 2019 (Online) 8th April Morning Slot
+4
-1
If $$f(x) = {\log _e}\left( {{{1 - x} \over {1 + x}}} \right)$$, $$\left| x \right| < 1$$ then $$f\left( {{{2x} \over {1 + {x^2}}}} \right)$$ is equal to
A
2f(x2)
B
2f(x)
C
(f(x))2
D
-2f(x)
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