1
JEE Main 2020 (Online) 2nd September Evening Slot
MCQ (Single Correct Answer)
+4
-1
Let f : R $$ \to $$ R be a function which satisfies
f(x + y) = f(x) + f(y) $$\forall $$ x, y $$ \in $$ R. If f(1) = 2 and
g(n) = $$\sum\limits_{k = 1}^{\left( {n - 1} \right)} {f\left( k \right)} $$, n $$ \in $$ N then the value of n, for which g(n) = 20, is :
A
20
B
9
C
5
D
4
2
JEE Main 2020 (Online) 2nd September Morning Slot
MCQ (Single Correct Answer)
+4
-1
If R = {(x, y) : x, y $$ \in $$ Z, x2 + 3y2 $$ \le $$ 8} is a relation on the set of integers Z, then the domain of R–1 is :
A
{0, 1}
B
{–2, –1, 1, 2}
C
{–1, 0, 1}
D
{–2, –1, 0, 1, 2}
3
JEE Main 2020 (Online) 2nd September Morning Slot
MCQ (Single Correct Answer)
+4
-1
The domain of the function
f(x) = $${\sin ^{ - 1}}\left( {{{\left| x \right| + 5} \over {{x^2} + 1}}} \right)$$ is (– $$\infty $$, -a]$$ \cup $$[a, $$\infty $$). Then a is equal to :
A
$${{\sqrt {17} - 1} \over 2}$$
B
$${{1 + \sqrt {17} } \over 2}$$
C
$${{\sqrt {17} } \over 2} + 1$$
D
$${{\sqrt {17} } \over 2}$$
4
JEE Main 2020 (Online) 9th January Evening Slot
MCQ (Single Correct Answer)
+4
-1
If A = {x $$ \in $$ R : |x| < 2} and B = {x $$ \in $$ R : |x – 2| $$ \ge $$ 3}; then :
A
A – B = [–1, 2)
B
A $$ \cup $$ B = R – (2, 5)
C
A $$ \cap $$ B = (–2, –1)
D
B – A = R – (–2, 5)
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