1
JEE Main 2019 (Online) 8th April Morning Slot
MCQ (Single Correct Answer)
+4
-1
Out of Syllabus
Change Language
The shortest distance between the line y = x and the curve y2 = x – 2 is :
A
$$7\over 4 \sqrt2$$
B
$$7\over8$$
C
$$11\over 4 \sqrt2$$
D
2
2
JEE Main 2019 (Online) 12th January Evening Slot
MCQ (Single Correct Answer)
+4
-1
Out of Syllabus
Change Language
The equation of a tangent to the parabola, x2 = 8y, which makes an angle $$\theta $$ with the positive directions of x-axis, is :
A
x = y cot $$\theta $$ – 2 tan $$\theta $$
B
y = x tan $$\theta $$ + 2 cot $$\theta $$
C
x = y cot $$\theta $$ + 2 tan $$\theta $$
D
y = x tan $$\theta $$ – 2 cot $$\theta $$
3
JEE Main 2019 (Online) 12th January Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
The maximum area (in sq. units) of a rectangle having its base on the x-axis and its other two vertices on the parabola, y = 12 – x2 such that the rectangle lies inside the parabola, is :
A
36
B
20$$\sqrt 2 $$
C
18$$\sqrt 3 $$
D
32
4
JEE Main 2019 (Online) 12th January Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
Let P(4, –4) and Q(9, 6) be two points on the parabola, y2 = 4x and let x be any point on the arc POQ of this parabola, where O is the vertex of this parabola, such that the area of $$\Delta $$PXQ is maximum. Then this maximum area (in sq. units) is :
A
$${{625} \over 4}$$
B
$${{125} \over 4}$$
C
$${{75} \over 2}$$
D
$${{125} \over 2}$$
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