JEE Main 2019 (Online) 12th April Evening Slot | Conic Sections Question 142 | Mathematics

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JEE Main 2019 (Online) 12th April Evening Slot

MCQ (Single Correct Answer)

-1

The equation of common tangent to the curves y² = 16x and xy = –4, is :

x – y + 4 = 0

x + y + 4 = 0

x – 2y + 16 = 0

2x – y + 2 = 0

JEE Main 2019 (Online) 12th April Evening Slot

MCQ (Single Correct Answer)

-1

The tangents to the curve y = (x – 2)² – 1 at its points of intersection with the line x – y = 3, intersect at the point :

$$\left( {{5 \over 2}, - 1} \right)$$

$$\left( { - {5 \over 2}, - 1} \right)$$

$$\left( {{5 \over 2},1} \right)$$

$$\left( { - {5 \over 2},1} \right)$$

JEE Main 2019 (Online) 12th April Evening Slot

MCQ (Single Correct Answer)

-1

An ellipse, with foci at (0, 2) and (0, –2) and minor axis of length 4, passes through which of the following points?

$$\left( {2,\sqrt 2 } \right)$$

$$\left( {2,2\sqrt 2 } \right)$$

$$\left( {\sqrt 2 ,2} \right)$$

$$\left( {1,2\sqrt 2 } \right)$$

JEE Main 2019 (Online) 12th April Morning Slot

MCQ (Single Correct Answer)

-1

Let P be the point of intersection of the common tangents to the parabola y² = 12x and the hyperbola 8x² – y² = 8. If S and S' denote the foci of the hyperbola where S lies on the positive x-axis then P divides SS' in a ratio :

14 : 13

13 : 11

5 : 4

2 : 1

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