1
JEE Main 2019 (Online) 12th April Evening Slot
+4
-1
Out of Syllabus
The equation of common tangent to the curves y2 = 16x and xy = –4, is :
A
x – y + 4 = 0
B
x + y + 4 = 0
C
x – 2y + 16 = 0
D
2x – y + 2 = 0
2
JEE Main 2019 (Online) 12th April Evening Slot
+4
-1
Out of Syllabus
The tangents to the curve y = (x – 2)2 – 1 at its points of intersection with the line x – y = 3, intersect at the point :
A
$$\left( {{5 \over 2}, - 1} \right)$$
B
$$\left( { - {5 \over 2}, - 1} \right)$$
C
$$\left( {{5 \over 2},1} \right)$$
D
$$\left( { - {5 \over 2},1} \right)$$
3
JEE Main 2019 (Online) 12th April Morning Slot
+4
-1
Out of Syllabus
Let P be the point of intersection of the common tangents to the parabola y2 = 12x and the hyperbola 8x2 – y2 = 8. If S and S' denote the foci of the hyperbola where S lies on the positive x-axis then P divides SS' in a ratio :
A
14 : 13
B
13 : 11
C
5 : 4
D
2 : 1
4
JEE Main 2019 (Online) 10th April Evening Slot
+4
-1
Out of Syllabus
If the line ax + y = c, touches both the curves x2 + y2 = 1 and y2 = 4$$\sqrt 2$$x , then |c| is equal to :
A
2
B
$$\sqrt 2$$
C
$${1 \over {\sqrt 2 }}$$
D
$${1 \over 2}$$
EXAM MAP
Medical
NEET