1
JEE Main 2020 (Online) 2nd September Evening Slot
+4
-1
The area (in sq. units) of an equilateral triangle inscribed in the parabola y2 = 8x, with one of its vertices on the vertex of this parabola, is :
A
$$256\sqrt 3$$
B
$$64\sqrt 3$$
C
$$128\sqrt 3$$
D
$$192\sqrt 3$$
2
JEE Main 2020 (Online) 2nd September Evening Slot
+4
-1
For some $$\theta \in \left( {0,{\pi \over 2}} \right)$$, if the eccentricity of the
hyperbola, x2–y2sec2$$\theta$$ = 10 is $$\sqrt 5$$ times the
eccentricity of the ellipse, x2sec2$$\theta$$ + y2 = 5, then the length of the latus rectum of the ellipse, is:
A
$$\sqrt {30}$$
B
$$2\sqrt 6$$
C
$${{4\sqrt 5 } \over 3}$$
D
$${{2\sqrt 5 } \over 3}$$
3
JEE Main 2020 (Online) 2nd September Morning Slot
+4
-1
A line parallel to the straight line 2x – y = 0 is tangent to the hyperbola
$${{{x^2}} \over 4} - {{{y^2}} \over 2} = 1$$ at the point $$\left( {{x_1},{y_1}} \right)$$. Then $$x_1^2 + 5y_1^2$$ is equal to :
A
5
B
6
C
10
D
8
4
JEE Main 2020 (Online) 9th January Evening Slot
+4
-1
The length of the minor axis (along y-axis) of an ellipse in the standard form is $${4 \over {\sqrt 3 }}$$. If this ellipse touches the line, x + 6y = 8; then its eccentricity is :
A
$${1 \over 3}\sqrt {{{11} \over 3}}$$
B
$${1 \over 2}\sqrt {{5 \over 3}}$$
C
$$\sqrt {{5 \over 6}}$$
D
$${1 \over 2}\sqrt {{{11} \over 3}}$$
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Physics
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Modern Physics
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