JEE Main 2018 (Offline) | Conic Sections Question 185 | Mathematics | JEE Main - ExamSIDE.com

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1

JEE Main 2018 (Offline)

MCQ (Single Correct Answer)

+4

-1

Tangents are drawn to the hyperbola 4x² - y² = 36 at the points P and Q.

If these tangents intersect at the point T(0, 3) then the area (in sq. units) of $$\Delta $$PTQ is :

A

$$36\sqrt 5 $$

B

$$45\sqrt 5 $$

C

$$54\sqrt 3 $$

D

$$60\sqrt 3 $$

2

JEE Main 2018 (Offline)

MCQ (Single Correct Answer)

+4

-1

Tangent and normal are drawn at P(16, 16) on the parabola y² = 16x, which intersect the axis of the parabola at A and B, respectively. If C is the centre of the circle through the points P, A and B and $$\angle $$CPB = $$\theta $$, then a value of tan$$\theta $$ is :

A

$${4 \over 3}$$

B

$${1 \over 2}$$

C

2

D

3

3

JEE Main 2018 (Online) 15th April Evening Slot

MCQ (Single Correct Answer)

+4

-1

Tangents drawn from the point ($$-$$8, 0) to the parabola y² = 8x touch the parabola at $$P$$ and $$Q.$$ If F is the focus of the parabola, then the area of the triangle PFQ (in sq. units) is equal to :

A

24

B

32

C

48

D

64

4

JEE Main 2018 (Online) 15th April Evening Slot

MCQ (Single Correct Answer)

+4

-1

A normal to the hyperbola, 4x² $$-$$ 9y² = 36 meets the co-ordinate axes $$x$$ and y at A and B, respectively. If the parallelogram OABP (O being the origin) is formed, then the ocus of P is :

A

4x² + 9y² = 121

B

9x² + 4y² = 169

C

4x² $$-$$ 9y² = 121

D

9x² $$-$$ 4y² = 169

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