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1
JEE Main 2020 (Online) 9th January Morning Slot
MCQ (Single Correct Answer)
+4
-1
If e1 and e2 are the eccentricities of the ellipse, $${{{x^2}} \over {18}} + {{{y^2}} \over 4} = 1$$ and the hyperbola, $${{{x^2}} \over 9} - {{{y^2}} \over 4} = 1$$ respectively and (e1, e2) is a point on the ellipse, 15x2 + 3y2 = k, then k is equal to :
A
17
B
16
C
15
D
14
2
JEE Main 2020 (Online) 8th January Evening Slot
MCQ (Single Correct Answer)
+4
-1
The length of the perpendicular from the origin, on the normal to the curve,
x2 + 2xy – 3y2 = 0 at the point (2,2) is
A
$$\sqrt 2 $$
B
$$4\sqrt 2 $$
C
2
D
$$2\sqrt 2 $$
3
JEE Main 2020 (Online) 8th January Evening Slot
MCQ (Single Correct Answer)
+4
-1
If a hyperbola passes through the point P(10, 16) and it has vertices at (± 6, 0), then the equation of the normal to it at P is
A
2x + 5y = 100
B
x + 3y = 58
C
x + 2y = 42
D
3x + 4y = 94
4
JEE Main 2020 (Online) 8th January Morning Slot
MCQ (Single Correct Answer)
+4
-1
Let the line y = mx and the ellipse 2x2 + y2 = 1 intersect at a ponit P in the first quadrant. If the normal to this ellipse at P meets the co-ordinate axes at $$\left( { - {1 \over {3\sqrt 2 }},0} \right)$$ and (0, $$\beta $$), then $$\beta $$ is equal to
A
$${{\sqrt 2 } \over 3}$$
B
$${2 \over 3}$$
C
$${{2\sqrt 2 } \over 3}$$
D
$${2 \over {\sqrt 3 }}$$
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