1
JEE Main 2019 (Online) 10th April Evening Slot
+4
-1
If 5x + 9 = 0 is the directrix of the hyperbola 16x2 – 9y2 = 144, then its corresponding focus is :
A
$$\left( {{5 \over 3},0} \right)$$
B
(5, 0)
C
(- 5, 0)
D
$$\left( { - {5 \over 3},0} \right)$$
2
JEE Main 2019 (Online) 10th April Morning Slot
+4
-1
If a directrix of a hyperbola centred at the origin and passing through the point (4, –2$$\sqrt 3$$ ) is 5x = 4$$\sqrt 5$$ and its eccentricity is e, then :
A
4e4 – 24e2 + 27 = 0
B
4e4 – 24e2 + 35 = 0
C
4e4 – 12e2 - 27 = 0
D
4e4 + 8e2 - 35 = 0
3
JEE Main 2019 (Online) 9th April Morning Slot
+4
-1
Out of Syllabus
If the line y = mx + 7$$\sqrt 3$$ is normal to the hyperbola $${{{x^2}} \over {24}} - {{{y^2}} \over {18}} = 1$$ , then a value of m is :
A
$${3 \over {\sqrt 5 }}$$
B
$${{\sqrt 15 } \over 2}$$
C
$${{\sqrt 5 } \over 2}$$
D
$${2 \over {\sqrt 5 }}$$
4
JEE Main 2019 (Online) 8th April Evening Slot
+4
-1
Out of Syllabus
If the eccentricity of the standard hyperbola passing through the point (4,6) is 2, then the equation of the tangent to the hyperbola at (4,6) is :
A
2x – y – 2 = 0
B
3x – 2y = 0
C
2x – 3y + 10 = 0
D
x – 2y + 8 = 0
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