JEE Main 2024 (Online) 5th April Evening Shift | Coordination Compounds Question 20 | Chemistry

The metal atom present in the complex MABXL (where A, B, X and L are unidentate ligands and $$\mathrm{M}$$ is metal) involves $$\mathrm{sp}^3$$ hybridization. The number of geometrical isomers exhibited by the complex is :

JEE Main 2024 (Online) 5th April Morning Shift

MCQ (Single Correct Answer)

-1

The correct order of ligands arranged in increasing field strength.

$$\mathrm{F}^{-}<\mathrm{Br}^{-}<\mathrm{I}^{-}<\mathrm{NH}_3$$

$$\mathrm{H}_2 \mathrm{O}<\mathrm{^{-}OH}<\mathrm{CN}^{-}<\mathrm{NH}_3$$

$$\mathrm{Br}^{-}<\mathrm{F}^{-}<\mathrm{H}_2 \mathrm{O}<\mathrm{NH}_3$$

$$\mathrm{Cl}^{-}<\mathrm{^{-}OH}<\mathrm{Br}^{-}<\mathrm{CN}^{-}$$

JEE Main 2024 (Online) 5th April Morning Shift

MCQ (Single Correct Answer)

-1

Which one of the following complexes will exhibit the least paramagnetic behaviour ? [Atomic number, $$\mathrm{Cr}=24, \mathrm{Mn}=25, \mathrm{Fe}=26, \mathrm{Co}=27$$]

$$\left[\mathrm{Fe}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{2+}$$

$$\left[\mathrm{Mn}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{2+}$$

$$\left[\mathrm{Co}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{2+}$$

$$\left[\mathrm{Cr}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{2+}$$

JEE Main 2024 (Online) 4th April Evening Shift

MCQ (Single Correct Answer)

-1

If an iron (III) complex with the formula $$\left[\mathrm{Fe}\left(\mathrm{NH}_3\right)_x(\mathrm{CN})_y\right]^-$$ has no electron in its $$e_g$$ orbital, then the value of $$x+y$$ is