In an estimation of sulphur by Carius method 0.2 g of the substance gave 0.6 g of $\mathrm{BaSO}_4$. The percentage of sulphur in the substance is $\_\_\_\_$%.

(Given molar mass in $\mathrm{g} \mathrm{mol}^{-1} \mathrm{~S}: 32, \mathrm{BaSO}_4: 231$ )

In sulphur estimation, $2.0 \times 10^{-3} \mathrm{~mol}$ of an organic compound $(\mathrm{X})$ (molar mass $76 \mathrm{~g} \mathrm{~mol}^{-1}$ ) gave 0.4813 g of barium sulphate (molar mass $233 \mathrm{~g} \mathrm{~mol}^{-1}$ ). The percentage of sulphur in the compound $(\mathrm{X})$ is $\_\_\_\_$ $\times 10^{-1} \%$ (Nearest integer)

2.0 g of a bromo hydrocarbon $(\mathrm{X})$ was subjected to Carius analysis, gave 3.36 g of AgBr . The percentage of carbon in the compound $(\mathrm{X})$ is $26.7 \%$. Total number of carbon atoms in the empirical formula for compound $(\mathrm{X})$ is $\_\_\_\_$ .

(Given molar mass in $\mathrm{g} \mathrm{mol}^{-1} \mathrm{H}: 1, \mathrm{C}: 12, \mathrm{Br}: 80, \mathrm{Ag}: 108$ )

Consider the following reactions sequence

When the product (P) is subjected to Carius analysis using AgNO₃, 1.0 g of the product (P) will produce _________ g of the precipitate of AgBr. (Nearest Integer)

(Given : molar mass in g mol^-1 C : 12, H : 1, O : 16, N : 14, Br : 80, Ag : 108)