JEE Main 2025 (Online) 28th January Evening Shift | Coordination Compounds Question 29 | Chemistry

JEE Main 2025 (Online) 28th January Evening Shift

MCQ (Single Correct Answer)

-1

Match List - I with List - II.

List - I (Complex)	List - II (Hybridisation of central metal ion)
(A) [CoF₆]^3-	(I) d²sp³
(B) [NiCl₄]^2-	(II) sp³
(C) [Co(NH₃)₆]³⁺	(III) sp³d²
(D) [Ni(CN)₄]^2-	(IV) dsp²

Choose the correct answer from the options given below:

(A)-(I), (B)-(II), (C)-(III), (D)-(IV)

(A)-(III), (B)-(IV), (C)-(I), (D)-(II)

(A)-(I), (B)-(IV), (C)-(III), (D)-(II)

(A)-(III), (B)-(II), (C)-(I), (D)-(IV)

JEE Main 2025 (Online) 24th January Evening Shift

MCQ (Single Correct Answer)

-1

The conditions and consequence that favours the $t_{2 \mathrm{~g}}{ }^3 \mathrm{e}_{\mathrm{g}}{ }^1$ configuration in a metal complex are :

strong field ligand, low spin complex

strong field ligand, high spin complex

weak field ligand, high spin complex

weak field ligand, low spin complex

JEE Main 2025 (Online) 24th January Evening Shift

MCQ (Single Correct Answer)

-1

When Ethane-1,2-diamine is added progressively to an aqueous solution of Nickel (II) chloride, the sequence of colour change observed will be:

Pale Blue $\rightarrow$ Blue $\rightarrow$ Green $\rightarrow$ Violet

Pale Blue $\rightarrow$ Blue $\rightarrow$ Violet $\rightarrow$ Green

Green $\rightarrow$ Pale Blue $\rightarrow$ Blue $\rightarrow$ Violet

Violet $\rightarrow$ Blue $\rightarrow$ Pale Blue $\rightarrow$ Green

JEE Main 2025 (Online) 24th January Morning Shift

MCQ (Single Correct Answer)

-1

One mole of the octahedral complex compound $\mathrm{Co}\left(\mathrm{NH}_3\right)_5 \mathrm{Cl}_3$ gives 3 moles of ions on dissolution in water. One mole of the same complex reacts with excess of $\mathrm{AgNO}_3$ solution to yield two moles of $\mathrm{AgCl}_{(\mathrm{s})}$. The structure of the complex is:

$\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_5 \mathrm{Cl}\right] \mathrm{Cl}_2$

$\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_4 \mathrm{Cl}\right] \cdot \mathrm{Cl}_2 \cdot \mathrm{NH}_3$

$\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_3 \mathrm{Cl}_3\right] \cdot 2 \mathrm{NH}_3$

$\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_4 \mathrm{Cl}_2\right] \cdot \mathrm{Cl} \cdot \mathrm{NH}_3$

PREVIOUS NEXT

JEE Main Subjects