JEE Main 2023 (Online) 31st January Morning Shift | Coordination Compounds Question 81 | Chemistry

JEE Main 2023 (Online) 31st January Morning Shift

MCQ (Single Correct Answer)

-1

Cobalt chloride when dissolved in water forms pink colored complex $$\underline{\mathrm{X}}$$ which has octahedral geometry. This solution on treating with conc $$\mathrm{HCl}$$ forms deep blue complex, $$\underline{\mathrm{Y}}$$ which has a $$\underline{\mathrm{Z}}$$ geometry. $$\mathrm{X}, \mathrm{Y}$$ and $$\mathrm{Z}$$, respectively, are

$$\mathrm{X}=\left[\mathrm{Co}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{2+}, \mathrm{Y}=\left[\mathrm{CoCl}_{4}\right]^{2-}, \mathrm{Z}=$$ Tetrahedral

$$\mathrm{X}=\left[\mathrm{Co}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{2+}, \mathrm{Y}=\left[\mathrm{CoCl}_{6}\right]^{3-}, \mathrm{Z}=$$ Octahedral

$$\mathrm{X}=\left[\mathrm{Co}\left(\mathrm{H}_{2} \mathrm{O}\right)_{4} \mathrm{Cl}_{2}\right]^{+}, \mathrm{Y}=\left[\mathrm{CoCl}_{4}\right]^{2-}, \mathrm{Z}=$$ Tetrahedral

$$\mathrm{X}=\left[\mathrm{Co}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{3+}, \mathrm{Y}=\left[\mathrm{CoCl}_{6}\right]^{3-}, \mathrm{Z}=$$ Octahedral

JEE Main 2023 (Online) 30th January Evening Shift

MCQ (Single Correct Answer)

-1

Match List I with List II:

List I (Complexes)		List II (Hybridisation)
A.	$\left[\mathrm{Ni}(\mathrm{CO})_{4}\right]$	I.	$\mathrm{sp}^{3}$
B.	$\left[\mathrm{Cu}\left(\mathrm{NH}_{3}\right)_{4}\right]^{2+}$	II.	dsp$^{2}$
C.	$\left[\mathrm{Fe}\left(\mathrm{NH}_{3}\right)_{6}\right]^{2+}$	III.	$\mathrm{sp}^{3}\mathrm{d}^{2}$
D.	$\left[\mathrm{Fe}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{2+}$	IV.	$\mathrm{d}^{2} \mathrm{sp}^{3}$

A-I, B-II, C-III, D-IV

A-II, B-I, C-III, D-IV

A-I, B-II, C-IV, D-III

A-II, B-I, C-IV, D-III

JEE Main 2023 (Online) 30th January Evening Shift

MCQ (Single Correct Answer)

-1

The $\mathrm{Cl}-\mathrm{Co}-\mathrm{Cl}$ bond angle values in a fac- $\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{3} \mathrm{Cl}_{3}\right]$ complex is/are :

$90^{\circ} ~\&~ 120^{\circ}$

$90^{\circ}$

$180^{\circ}$

$90^{\circ} ~\& ~180^{\circ}$

JEE Main 2023 (Online) 30th January Morning Shift

MCQ (Single Correct Answer)

-1

To inhibit the growth of tumours, identify the compounds used from the following :

A. EDTA

B. Coordination Compounds of Pt

C. D - Penicillamine

D. Cis - Platin

Choose the correct answer from the option given below :

A and B Only

C and D Only

B and D Only

A and C Only

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