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JEE Main 2025 (Online) 2nd April Evening Shift
Numerical
+4
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JEE Main 2025 (Online) 2nd April Evening Shift Chemistry - Haloalkanes and Haloarenes Question 4 English

Consider the above sequence of reactions. 151 g of 2-bromopentane is made to react. Yield of major product P is $80 \%$ whereas Q is $100 \%$.

Mass of product Q obtained is________ g.

(Given molar mass in $\mathrm{g} \mathrm{mol}^{-1} \mathrm{H}: 1, \mathrm{C}: 12, \mathrm{O}: 16, \mathrm{Br}: 80$ )

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2
JEE Main 2025 (Online) 28th January Morning Shift
Numerical
+4
-1
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Consider the following sequence of reactions:

JEE Main 2025 (Online) 28th January Morning Shift Chemistry - Haloalkanes and Haloarenes Question 6 English

11.25 mg of chlorobenzene will produce ___________$\times 10^{-1} \mathrm{mg}$ of product B.

(Consider the reactions result in complete conversion.)

[Given molar mass of $\mathrm{C}, \mathrm{H}, \mathrm{O}, \mathrm{N}$ and Cl as $12,1,16,14$ and $35.5 \mathrm{~g} \mathrm{~mol}^{-1}$ respectively]

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3
JEE Main 2024 (Online) 6th April Evening Shift
Numerical
+4
-1
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JEE Main 2024 (Online) 6th April Evening Shift Chemistry - Haloalkanes and Haloarenes Question 18 English

The ratio of number of oxygen atoms to bromine atoms in the product Q is _________ $$\times 10^{-1}$$.

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4
JEE Main 2024 (Online) 5th April Morning Shift
Numerical
+4
-1
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The number of halobenzenes from the following that can be prepared by Sandmeyer's reaction is _________

JEE Main 2024 (Online) 5th April Morning Shift Chemistry - Haloalkanes and Haloarenes Question 20 English

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