Which of the following sequences of hybridisation, geometry and magnetic nature are correct for the given coordination compounds?

A. $\left[\mathrm{NiCl}_4\right]^{2-}-\mathrm{sp}^3$, tetrahedral, paramagnetic

B. $\left[\mathrm{Ni}\left(\mathrm{NH}_3\right)_6\right]^{2+}-\mathrm{sp}^3 \mathrm{~d}^2$, octahedral, paramagnetic

C. $\left[\mathrm{Ni}(\mathrm{CO})_4\right]-\mathrm{sp}^3$, tetrahedral, paramagnetic

D. $\left[\mathrm{Ni}(\mathrm{CN})_4\right]^{2-}-\mathrm{dsp}^2$, square planar, diamagnetic

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$$ \text { Match the LIST-I with LIST-II } $$

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Which of the following are true about the energy of the given d-orbitals of a tetrahedral complex?

A. $\mathrm{d}_{x y}=\mathrm{d}_{x z}>\mathrm{d}_{{x^2}-\mathrm{y}^2}$

B. $\mathrm{d}_{x y}=\mathrm{d}_{y z}>\mathrm{d}_{z^2}$

C. $\mathrm{d}_{x^2-y^2}>\mathrm{d}_{z^2}>\mathrm{d}_{x z}$

D. $\mathrm{d}_{{x^2}-y^2}=\mathrm{d}_{z^2}<\mathrm{d}_{x z}$

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Given below are two statements :

Statement I : Presence of large number of unpaired electrons in transition metal atoms results in higher enthalpies of their atomisation.

Statement II : $\quad \mathrm{d}_{x y}=\mathrm{d}_{x z}=\mathrm{d}_{y z}<\mathrm{d}_{x^2-y^2}=\mathrm{d}_{z^2}$ and $\mathrm{d}_{x^2-y^2}=\mathrm{d}_{z^2}<\mathrm{d}_{x y}=\mathrm{d}_{x z}=\mathrm{d}_{y z}$ are the d-orbital splittings in $\left[\mathrm{Fe}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{3+}$ and $\left[\mathrm{Ni}(\mathrm{Cl})_4\right]^{2-}$ complex ions respectively.

In the light of the above statements, choose the correct answer from the options given below :