Thiosulphate reacts differently with iodine and bromine in the reactions given below:
$$\begin{aligned} & 2 \mathrm{~S}_2 \mathrm{O}_3^{2-}+\mathrm{I}_2 \rightarrow \mathrm{S}_4 \mathrm{O}_6^{2-}+2 \mathrm{I}^{-} \\ & \mathrm{S}_2 \mathrm{O}_3^{2-}+5 \mathrm{Br}_2+5 \mathrm{H}_2 \mathrm{O} \rightarrow 2 \mathrm{SO}_4^{2-}+4 \mathrm{Br}^{-}+10 \mathrm{H}^{+} \end{aligned}$$
Which of the following statement justifies the above dual behaviour of thiosulphate?
The number of ions from the following that are expected to behave as oxidising agent is :
$$\mathrm{Sn}^{4+}, \mathrm{Sn}^{2+}, \mathrm{Pb}^{2+}, \mathrm{Tl}^{3+}, \mathrm{Pb}^{4+}, \mathrm{Tl}^{+}$$
Match List I with List II.
LIST I Reaction |
LIST II Type of redox reaction |
||
---|---|---|---|
A. | $$ \mathrm{N}_{2(\mathrm{~g})}+\mathrm{O}_{2(\mathrm{~g})} \rightarrow 2 \mathrm{NO}_{(\mathrm{g})} $$ |
I. | Decomposition |
B. | $$ 2 \mathrm{~Pb}\left(\mathrm{NO}_3\right)_{2(\mathrm{~s})} \rightarrow 2 \mathrm{PbO}_{(\mathrm{s})}+4 \mathrm{NO}_{2(\mathrm{~g})}+\mathrm{O}_{2(\mathrm{~g})} $$ |
II. | Displacement |
C. | $$ 2 \mathrm{Na}_{(\mathrm{s})}+2 \mathrm{H}_2 \mathrm{O}_{(\mathrm{l})} \rightarrow 2 \mathrm{NaOH}_{(\mathrm{aq} .)}+\mathrm{H}_{2(\mathrm{~g})} $$ |
III. | Disproportionation |
D. | $$ 2 \mathrm{NO}_{2(\mathrm{~g})}+2^{-} \mathrm{OH}(\text { aq. }) \rightarrow \mathrm{NO}_{2(\mathrm{aq} .)}^{-}+\mathrm{NO}_{3(\text { aq. })}^{-}+\mathrm{H}_2 \mathrm{O}_{(\mathrm{l})} $$ |
IV. | Combination |
Choose the correct answer from the options given below :
When $$\mathrm{MnO}_2$$ and $$\mathrm{H}_2 \mathrm{SO}_4$$ is added to a salt $$(\mathrm{A})$$, the greenish yellow gas liberated as salt (A) is :