JEE Main 2024 (Online) 9th April Evening Shift

MCQ (Single Correct Answer)

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Match List I with List II

	LIST I (Cell)		LIST II (Use/Property/Reaction)
A.	Leclanche cell	I.	Converts energy of combustion into electrical energy
B.	Ni - Cd cell	II.	Does not involve any ion in solution and is used in hearing aids
C.	Fuel cell	III.	Rechargeable
D.	Mercury cell	IV.	Reaction at anode $$\mathrm{Zn} \rightarrow \mathrm{Zn}^{2+}+2 \mathrm{e}^{-}$$

Choose the correct answer from the options given below :

A-III, B-I, C-IV, D-II

A-I, B-II, C-III, D-IV

A-IV, B-III, C-I, D-II

A-II, B-III, C-IV, D-I

JEE Main 2024 (Online) 9th April Evening Shift

MCQ (Single Correct Answer)

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Which out of the following is a correct equation to show change in molar conductivity with respect to concentration for a weak electrolyte, if the symbols carry their usual meaning :

$$\Lambda_{\mathrm{m}}-\Lambda_{\mathrm{m}}^{\circ}+\mathrm{AC}^{\frac{1}{2}}=0$$

$$\Lambda_{\mathrm{m}}^2 \mathrm{C}+\mathrm{K}_{\mathrm{a}} \Lambda_{\mathrm{m}}^{\mathrm{o}^2}-\mathrm{K}_{\mathrm{a}} \Lambda_{\mathrm{m}} \Lambda_{\mathrm{m}}^{\circ}=0$$

$$\Lambda_{\mathrm{m}}-\Lambda_{\mathrm{m}}^{\circ}-\mathrm{AC}^{\frac{1}{2}}=0$$

$$\Lambda_{\mathrm{m}}^2 \mathrm{C}-\mathrm{K}_{\mathrm{a}} \Lambda_{\mathrm{m}}^{\circ 2}+\mathrm{K}_{\mathrm{a}} \Lambda_{\mathrm{m}} \Lambda_{\mathrm{m}}^{\circ}=0$$

JEE Main 2024 (Online) 9th April Morning Shift

MCQ (Single Correct Answer)

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The molar conductivity for electrolytes $$A$$ and $$B$$ are plotted against $$C^{3 / 2}$$ as shown below. Electrolytes $$A$$ and $$B$$ respectively are:

JEE Main 2024 (Online) 9th April Morning Shift Chemistry - Electrochemistry Question 15 English

A - weak electrolyte $$\quad$$ B - weak electrolyte

A - weak electrolyte $$\quad$$ B - strong electrolyte

A - strong electrolyte $$\quad$$ B - strong electrolyte

A - strong electrolyte $$\quad$$ B - weak electrolyte

JEE Main 2024 (Online) 8th April Evening Shift

MCQ (Single Correct Answer)

-1

The emf of cell $$\mathrm{Tl}\left|\underset{(0.001 \mathrm{M})}{\mathrm{Tl}^{+}}\right| \underset{(0.01 \mathrm{M})}{\mathrm{Cu}^{2+}} \mid \mathrm{Cu}$$ is $$0.83 \mathrm{~V}$$ at $$298 \mathrm{~K}$$. It could be increased by :

increasing concentration of $$\mathrm{Tl}^{+}$$ ions

increasing concentration of $$\mathrm{Cu}^{2+}$$ ions

increasing concentration of both $$\mathrm{Tl}^{+}$$ and $$\mathrm{Cu}^{2+}$$ ions

decreasing concentration of both $$\mathrm{Tl}^{+}$$ and $$\mathrm{Cu}^{2+}$$ ions

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