1
JEE Main 2026 (Online) 6th April Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

$$ \text { Consider the following reaction. } $$

JEE Main 2026 (Online) 6th April Evening Shift Chemistry - Alcohols, Phenols and Ethers Question 7 English

Statement I : In the above reaction, product formed will be a mixture of benzyl alcohol and iodobenzene.

Statement II : In the above reaction, the $-\mathrm{O}-\mathrm{CH}_2-$ bond is cleaved to give the product.

In the light of the above statements, choose the correct answer from the options given below :

A

Both Statement I and Statement II are true

B

Both Statement I and Statement II are false

C

Statement I is true but Statement II is false

D

Statement I is false but Statement II is true

2
JEE Main 2026 (Online) 6th April Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

Consider the following reactions. Total number of electrons in the $\pi$ bonds and lone pair of electrons in the product $(X)$ is :

JEE Main 2026 (Online) 6th April Evening Shift Chemistry - Alcohols, Phenols and Ethers Question 6 English
A

12

B

16

C

14

D

18

3
JEE Main 2026 (Online) 6th April Morning Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

Consider the following sequence of reactions

JEE Main 2026 (Online) 6th April Morning Shift Chemistry - Alcohols, Phenols and Ethers Question 4 English

The major product P is :

A
JEE Main 2026 (Online) 6th April Morning Shift Chemistry - Alcohols, Phenols and Ethers Question 4 English Option 1
B
JEE Main 2026 (Online) 6th April Morning Shift Chemistry - Alcohols, Phenols and Ethers Question 4 English Option 2
C
JEE Main 2026 (Online) 6th April Morning Shift Chemistry - Alcohols, Phenols and Ethers Question 4 English Option 3
D
JEE Main 2026 (Online) 6th April Morning Shift Chemistry - Alcohols, Phenols and Ethers Question 4 English Option 4
4
JEE Main 2026 (Online) 5th April Morning Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

Consider compounds $\mathrm{A}, \mathrm{B}$ and C with following structural formulae

$$ \begin{aligned} & \mathrm{A}=\mathrm{CH}_3-\mathrm{CH}_2-\mathrm{CH}_2-\mathrm{CH}_2-\mathrm{CH}_2-\mathrm{OH} \\ & \mathrm{~B}=\mathrm{CH}_2=\mathrm{CH}-\mathrm{CH}_2-\mathrm{CH}_2-\mathrm{CH}_3 \\ & \mathrm{C}=\mathrm{HO}-\mathrm{CH}_2-\mathrm{CH}_2-\mathrm{CH}(\mathrm{OH})-\mathrm{CH}_3 \end{aligned} $$

For the conversion of B from A , reagent (D) required is $\_\_\_\_$ and structural formula of product $(\mathrm{E})$ obtained when C undergoes same reaction using excess reagent (D) is $\_\_\_\_$ .

A

$$ \begin{array}{|c|c|} \hline \text { D } & \text { E } \\ \hline \text { Conc. } \mathrm{H}_2 \mathrm{SO}_4 & \mathrm{CH}_2=\mathrm{CH}-\mathrm{CH}(\mathrm{OH}) \mathrm{CH}_3 \\ \hline \end{array} $$

B

$$ \begin{array}{|c|c|} \hline \mathrm{D} & \mathrm{E} \\ \hline \mathrm{PCC} & \mathrm{HO}-\mathrm{CH}_2-\mathrm{CH}_2-\mathrm{CH}=\mathrm{CH}_2 \\ \hline \end{array} $$

C

$$ \begin{array}{|c|c|} \hline \text { D } & \text { E } \\ \hline \text { PCC } & \mathrm{CH}_2=\mathrm{CH}-\mathrm{CH}=\mathrm{CH}_2 \\ \hline \end{array} $$

D

$$ \begin{array}{|c|c|} \hline \text { D } & \mathrm{E} \\ \hline \text { Conc. } \mathrm{H}_2 \mathrm{SO}_4 \text { or } \mathrm{H}_3 \mathrm{PO}_4 & \mathrm{CH}_2=\mathrm{CH}-\mathrm{CH}=\mathrm{CH}_2 \\ \hline \end{array} $$

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