JEE Main 2018 (Online) 15th April Evening Slot | Coordination Compounds Question 161 | Chemistry

JEE Main 2018 (Online) 15th April Evening Slot

MCQ (Single Correct Answer)

-1

The correct order of spin-only magnetic moments among the following is :
(Atomic number : Mn = 25, Co = 27, Ni = 28, Zn = 30)

[ZnCl₄]^2- > [NiCl₄]^2- > [CoCl₄]^2- > [MnCl₄]^2-

[CoCl₄]^2- > [MnCl₄]^2- > [NiCl₄]^2- > [ZnCl₄]^2-

[NiCl₄]^2- > [CoCl₄]^2- > [MnCl₄]^2- > [ZnCl₄]^2-

[MnCl₄]^2- > [CoCl₄]^2- > [NiCl₄]^2- > [ZnCl₄]^2-

JEE Main 2018 (Online) 15th April Evening Slot

MCQ (Single Correct Answer)

-1

The total number of possible isomers for square-planar [Pt(Cl)(NO₂)(NO₃)(SCN)]^2- is :

JEE Main 2018 (Online) 15th April Morning Slot

MCQ (Single Correct Answer)

-1

The correct combination is :

[Ni(CN)₄]^2- $$-$$ tetrahedral ;

[Ni(CO)₄] $$-$$ paramagnetic

[Ni(Cl)₄]^2- $$-$$ paramagnetic ;

[Ni(CO)₄] $$-$$ tetrahedral

[Ni(Cl)₄]^2- $$-$$ square-planar ;

[Ni(CN)₄] ^2-$$-$$ paramagnetic

[Ni(Cl)₄]^2- $$-$$ diamagnetic ;

[Ni(CO)₄] $$-$$square-planar

JEE Main 2017 (Online) 9th April Morning Slot

MCQ (Single Correct Answer)

-1

[Co₂(CO)₈] displays :

one Co−Co bond, six terminal CO and two bridging CO

one Co−Co bond, four terminal CO and four bridging CO

no Co−Co bond, six terminal CO and two bridging CO

no Co−Co bond, four terminal CO and four bridging CO

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