1
JEE Main 2018 (Online) 15th April Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
The correct order of spin-only magnetic moments among the following is :
(Atomic number : Mn = 25, Co = 27, Ni = 28, Zn = 30)
A
[ZnCl4]2- > [NiCl4]2- > [CoCl4]2- > [MnCl4]2-
B
[CoCl4]2- > [MnCl4]2- > [NiCl4]2- > [ZnCl4]2-
C
[NiCl4]2- > [CoCl4]2- > [MnCl4]2- > [ZnCl4]2-
D
[MnCl4]2- > [CoCl4]2- > [NiCl4]2- > [ZnCl4]2-
2
JEE Main 2018 (Online) 15th April Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
The total number of possible isomers for square-planar [Pt(Cl)(NO2)(NO3)(SCN)]2- is :
A
8
B
12
C
16
D
24
3
JEE Main 2018 (Online) 15th April Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
The correct combination is :
A
[Ni(CN)4]2- $$-$$ tetrahedral ;

[Ni(CO)4] $$-$$ paramagnetic
B
[Ni(Cl)4]2- $$-$$ paramagnetic ;

[Ni(CO)4] $$-$$ tetrahedral
C
[Ni(Cl)4]2- $$-$$ square-planar ;

[Ni(CN)4] 2-$$-$$ paramagnetic
D
[Ni(Cl)4]2- $$-$$ diamagnetic ;

[Ni(CO)4] $$-$$square-planar
4
JEE Main 2017 (Online) 9th April Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
[Co2(CO)8] displays :
A
one Co−Co bond, six terminal CO and two bridging CO
B
one Co−Co bond, four terminal CO and four bridging CO
C
no Co−Co bond, six terminal CO and two bridging CO
D
no Co−Co bond, four terminal CO and four bridging CO
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