1
JEE Main 2025 (Online) 7th April Evening Shift
Numerical
+4
-1
Change Language

Identify the structure of the final product (D) in the following sequence of the reactions :

JEE Main 2025 (Online) 7th April Evening Shift Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 6 English

Total number of $\mathrm{sp}^2$ hybridised carbon atoms in product D is ____________.

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2
JEE Main 2025 (Online) 7th April Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

Let f : ℝ $$ \to $$ ℝ be a polynomial function of degree four having extreme values at x = 4 and x = 5. If $ \lim\limits_{x \to 0} \frac{f(x)}{x^2} = 5 $, then f(2) is equal to :

A

8

B

10

C

12

D

14

3
JEE Main 2025 (Online) 7th April Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

Let y = y(x) be the solution of the differential equation $(x^2 + 1)y' - 2xy = (x^4 + 2x^2 + 1)\cos x$,

$y(0) = 1$. Then $ \int\limits_{-3}^{3} y(x) \, dx $ is :

A

36

B

24

C

18

D

30

4
JEE Main 2025 (Online) 7th April Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

If the locus of z ∈ ℂ, such that Re$ \left( \frac{z - 1}{2z + i} \right) + \text{Re} \left( \frac{\overline{z} - 1}{2\overline{z} - i} \right) = 2 $, is a circle of radius r and center $(a, b)$, then $ \frac{15ab}{r^2} $ is equal to :

A

16

B

24

C

12

D

18

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