1
JEE Main 2025 (Online) 7th April Evening Shift
MCQ (Single Correct Answer)
+4
-1

Match List - I with List - II.

List - I List - II
(A) Isothermal (I) ΔW (work done) = 0
(B) Adiabatic (II) ΔQ (supplied heat) = 0
(C) Isobaric (III) ΔU (change in internal energy) ≠ 0
(D) Isochoric (IV) ΔU = 0

Choose the correct answer from the options given below :

A

(A)-(III), (B)-(II), (C)-(I), (D)-(IV)

B

(A)-(II), (B)-(IV), (C)-(I), (D)-(III)

C

(A)-(IV), (B)-(II), (C)-(III), (D)-(I)

D

(A)-(IV), (B)-(I), (C)-(III), (D)-(II)

2
JEE Main 2025 (Online) 7th April Evening Shift
Numerical
+4
-1
M and R be the mass and radius of a disc. A small disc of radius $\mathrm{R} / 3$ is removed from the bigger disc as shown in figure. The moment of inertia of remaining part of bigger disc about an axis $A B$ passing through the centre $O$ and perpendicular to the plane of disc is $\frac{4}{x} \mathrm{MR}^2$. The value of $x$ is ____________. JEE Main 2025 (Online) 7th April Evening Shift Physics - Rotational Motion Question 6 English
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3
JEE Main 2025 (Online) 7th April Evening Shift
Numerical
+4
-1
Two cylindrical rods A and B made of different materials, are joined in a straight line. The ratios of lengths, radii and thermal conductivites of these rods are: $\frac{\mathrm{L}_{\mathrm{A}}}{\mathrm{L}_{\mathrm{B}}}=\frac{1}{2}, \frac{\mathrm{r}_{\mathrm{A}}}{\mathrm{r}_{\mathrm{B}}}=2$ and $\frac{\mathrm{K}_{\mathrm{A}}}{\mathrm{K}_{\mathrm{B}}}=\frac{1}{2}$. The free ends of rods A and B are maintained at 400 K , 200 K , respectively. The temperature of rods interface is ______________ $K$, when equilibrium is established.
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4
JEE Main 2025 (Online) 7th April Evening Shift
Numerical
+4
-1
The electric field in a region is given by $\overrightarrow{\mathrm{E}}=(2 \hat{i}+4 \hat{j}+6 \hat{k}) \times 10^3 \mathrm{~N} / \mathrm{C}$. The flux of the field through a rectangular surface parallel to $x-z$ plane is $6.0 \,\mathrm{Nm}^2 \mathrm{C}^{-1}$. The area of the surface is _____________ $\mathrm{cm}^2$.
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