1
JEE Main 2025 (Online) 7th April Evening Shift
MCQ (Single Correct Answer)
+4
-1

Match List - I with List - II.

List - I (Conversion) List - II (Reagents, Conditions used)
JEE Main 2025 (Online) 7th April Evening Shift Chemistry - Compounds Containing Nitrogen Question 4 English 1 (I) Warm H2O
JEE Main 2025 (Online) 7th April Evening Shift Chemistry - Compounds Containing Nitrogen Question 4 English 2 (II) (a) NaOH, 368K; (b) H3O+
JEE Main 2025 (Online) 7th April Evening Shift Chemistry - Compounds Containing Nitrogen Question 4 English 3 (III) (a) NaOH, 443K; (b) H3O+
JEE Main 2025 (Online) 7th April Evening Shift Chemistry - Compounds Containing Nitrogen Question 4 English 4 (IV) (a) NaOH, 623K, 300 atm; (b) H3O+

Choose the correct answer from the options given below :

A

(A)-(II), (B)-(III), (C)-(I), (D)-(IV)

B

(A)-(III), (B)-(IV), (C)-(II), (D)-(I)

C

(A)-(IV), (B)-(III), (C)-(I), (D)-(II)

D

(A)-(IV), (B)-(III), (C)-(II), (D)-(I)

2
JEE Main 2025 (Online) 7th April Evening Shift
MCQ (Single Correct Answer)
+4
-1

Liquid A and B form an ideal solution. The vapour pressures of pure liquids A and B are 350 and 750 mm Hg respectively at the same temperature. If $x_A$ and $x_B$ are the mole fraction of A and B in solution while $y_A$ and $y_B$ are the mole fraction of A and B in vapour phase, then,

A

$(x_A - y_A) < (x_B - y_B)$

B

$\frac{x_A}{x_B} = \frac{y_A}{y_B}$

C

$\frac{x_A}{x_B} < \frac{y_A}{y_B}$

D

$\frac{x_A}{x_B} > \frac{y_A}{y_B}$

3
JEE Main 2025 (Online) 7th April Evening Shift
MCQ (Single Correct Answer)
+4
-1

Match List - I with List - II.

List - I List - II
(A) Solution of chloroform and acetone (I) Minimum boiling azeotrope
(B) Solution of ethanol and water (II) Dimerizes
(C) Solution of benzene and toluene (III) Maximum boiling azeotrope
(D) Solution of acetic acid in benzene (IV) ΔVmix = 0

Choose the correct answer from the options given below :

A

(A)-(III), (B)-(I), (C)-(IV), (D)-(II)

B

(A)-(III), (B)-(IV), (C)-(I), (D)-(II)

C

(A)-(II), (B)-(I), (C)-(IV), (D)-(III)

D

(A)-(II), (B)-(IV), (C)-(I), (D)-(III)

4
JEE Main 2025 (Online) 7th April Evening Shift
MCQ (Single Correct Answer)
+4
-1

The hydration energies of $K^+$ and $Cl^-$ are $-x$ and $-y$ kJ/mol respectively. If the lattice energy of KCl is $-z$ kJ/mol, then the heat of solution of KCl is :

A

$x + y + z$

B

$z - (x + y)$

C

$-z - (x + y)$

D

$x - y - z$

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