1
JEE Main 2025 (Online) 2nd April Morning Shift
MCQ (Single Correct Answer)
+4
-1

A monochromatic light is incident on a metallic plate having work function $\phi$. An electron, emitted normally to the plate from a point A with maximum kinetic energy, enters a constant magnetic field, perpendicular to the initial velocity of electron. The electron passes through a curve and hits back the plate at a point $B$. The distance between $A$ and $B$ is : (Given : The magnitude of charge of an electron is e and mass is $\mathrm{m}, \mathrm{h}$ is Planck's constant and c is velocity of light. Take the magnetic field exists throughout the path of electron)

A
$\sqrt{2 m\left(\frac{h c}{\lambda}-\phi\right)} / \mathrm{eB}$
B
$\sqrt{8 \mathrm{~m}\left(\frac{\mathrm{hc}}{\lambda}-\phi\right)} / \mathrm{eB}$
C
$\sqrt{\mathrm{m}(\mathrm{hc} / \lambda-\phi)} / \mathrm{eB}$
D
$2 \sqrt{\mathrm{~m}(\mathrm{hc} / \lambda-\phi)} / \mathrm{eB}$
2
JEE Main 2025 (Online) 2nd April Morning Shift
MCQ (Single Correct Answer)
+4
-1

JEE Main 2025 (Online) 2nd April Morning Shift Physics - Geometrical Optics Question 9 English

A spherical surface separates two media of refractive indices 1 and 1.5 as shown in figure. Distance of the image of an object ' O ', is :

( C is the center of curvature of the spherical surface and R is the radius of curvature)

A
0.24 m left to the spherical surface
B
0.24 m right to the spherical surface
C
0.4 m left to the spherical surface
D
0.4 m right to the spherical surface
3
JEE Main 2025 (Online) 2nd April Morning Shift
MCQ (Single Correct Answer)
+4
-1

A river is flowing from west to east direction with speed of $9 \mathrm{~km} \mathrm{~h}^{-1}$. If a boat capable of moving at a maximum speed of $27 \mathrm{~km} \mathrm{~h}^{-1}$ in still water, crosses the river in half a minute, while moving with maximum speed at an angle of $150^{\circ}$ to direction of river flow, then the width of the river is :

A
112.5 m
B
75 m
C
300 m
D
$112.5 \times \sqrt{3} \mathrm{~m}$
4
JEE Main 2025 (Online) 2nd April Morning Shift
MCQ (Single Correct Answer)
+4
-1

Moment of inertia of a rod of mass ' M ' and length ' L ' about an axis passing through its center and normal to its length is ' $\alpha$ '. Now the rod is cut into two equal parts and these parts are joined symmetrically to form a cross shape. Moment of inertia of cross about an axis passing through its center and normal to plane containing cross is :

A
$\alpha / 4$
B
$\alpha / 8$
C
$\alpha$
D
$\alpha / 2$
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