1
JEE Main 2025 (Online) 2nd April Morning Shift
MCQ (Single Correct Answer)
+4
-1

Designate whether each of the following compounds is aromatic or not aromatic.

JEE Main 2025 (Online) 2nd April Morning Shift Chemistry - Basics of Organic Chemistry Question 5 English

A
$a, c, d, e, h$ aromatic and $b, f, g$ not aromatic
B
$b, e, f, g$ aromatic and $a, c, d, h$ not aromatic
C
$a, b, c, d$ aromatic and $e, f, g, h$ not aromatic
D
e, $g$ aromatic and $a, b, c, d, f, h$ not aromatic
2
JEE Main 2025 (Online) 2nd April Morning Shift
MCQ (Single Correct Answer)
+4
-1

Choose the correct tests with respective observations.

(A) $\mathrm{CuSO}_4$ (acidified with acetic acid) $+\mathrm{K}_4\left[\mathrm{Fe}(\mathrm{CN})_6\right] \rightarrow$ Chocolate brown precipitate.

(B) $\mathrm{FeCl}_3+\mathrm{K}_4\left[\mathrm{Fe}(\mathrm{CN})_6\right] \rightarrow$ Prussian blue precipitate.

(C) $\mathrm{ZnCl}_2+\mathrm{K}_4\left[\mathrm{Fe}(\mathrm{CN})_6\right]$, neutralised with $\mathrm{NH}_4 \mathrm{OH} \rightarrow$ White or bluish white precipitate.

(D) $\mathrm{MgCl}_2+\mathrm{K}_4\left[\mathrm{Fe}(\mathrm{CN})_6\right] \rightarrow$ Blue precipitate.

(E) $\mathrm{BaCl}_2+\mathrm{K}_4\left[\mathrm{Fe}(\mathrm{CN})_6\right]$, neutralised with $\mathrm{NaOH} \rightarrow$ White precipitate.

Choose the correct answer from the options given below :

A
A, D and E only
B
A, B and C only
C
B, D and E only
D
C, D and E only
3
JEE Main 2025 (Online) 2nd April Morning Shift
MCQ (Single Correct Answer)
+4
-1

A solution is made by mixing one mole of volatile liquid $A$ with 3 moles of volatile liquid $B$. The vapour pressure of pure A is 200 mm Hg and that of the solution is 500 mm Hg . The vapour pressure of pure B and the least volatile component of the solution, respectively, are:

A
$1400 \mathrm{~mm} \mathrm{~Hg}, \mathrm{A}$
B
$1400 \mathrm{~mm} \mathrm{~Hg}, B$
C
$600 \mathrm{~mm} \mathrm{~Hg}, \mathrm{A}$
D
$600 \mathrm{~mm} \mathrm{~Hg}, \mathrm{B}$
4
JEE Main 2025 (Online) 2nd April Morning Shift
MCQ (Single Correct Answer)
+4
-1

A molecule with the formula $\mathrm{AX}_4 \mathrm{Y}$ has all it's elements from p-block. Element A is rarest, monoatomic, non-radioactive from its group and has the lowest ionization enthalpy value among $\mathrm{A}, \mathrm{X}$ and Y . Elements X and Y have first and second highest electronegativity values respectively among all the known elements. The shape of the molecule is:

A
Pentagonal planar
B
Square pyramidal
C
Trigonal bipyramidal
D
Octahedral
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