1
JEE Main 2025 (Online) 2nd April Morning Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

Given below are two statements :

Statement (I) : In octahedral complexes, when $\Delta_0<\mathrm{P}$ high spin complexes are formed. When $\Delta_0>P$ low spin complexes are formed.

Statement (II) : In tetrahedral complexes because of $\Delta_t < P$, low spin complexes are rarely formed.

In the light of the above statements, choose the most appropriate answer from the options given below :

A
Both Statement I and Statement II are incorrect
B
Statement I is correct but Statement II is incorrect
C
Statement I is incorrect but Statement II is correct
D
Both Statement I and Statement II are correct
2
JEE Main 2025 (Online) 2nd April Morning Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

On complete combustion 1.0 g of an organic compound $(\mathrm{X})$ gave 1.46 g of $\mathrm{CO}_2$ and 0.567 g of $\mathrm{H}_2 \mathrm{O}$. The empirical formula mass of compound $(\mathrm{X})$ is __________ g. (Given molar mass in $\mathrm{g} \mathrm{mol}^{-1} \mathrm{C}: 12, \mathrm{H}: 1, \mathrm{O}: 16$ )

A
60
B
45
C
30
D
15
3
JEE Main 2025 (Online) 2nd April Morning Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

Given below are two statements:

Statement I : Vanilin JEE Main 2025 (Online) 2nd April Morning Shift Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 11 English 1 will react with NaOH and also with Tollen's reagent.

Statement II : Vanilin JEE Main 2025 (Online) 2nd April Morning Shift Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 11 English 2 will undergo self aldol condensation very easily.

In the light of the above statements, choose the most appropriate answer from the options given below :

A
Statement I is correct but Statement II is incorrect
B
Both Statement I and Statement II are correct
C
Both Statement I and Statement II are incorrect
D
Statement I is incorrect but Statement II is correct
4
JEE Main 2025 (Online) 2nd April Morning Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

An optically active alkyl halide $\mathrm{C}_4 \mathrm{H}_9 \mathrm{Br}[\mathrm{A}]$ reacts with hot KOH dissolved in ethanol and forms alkene $[B]$ as major product which reacts with bromine to give dibromide $[C]$. The compound [C] is converted into a gas [D] upon reacting with alcoholic $\mathrm{NaNH}_2$. During hydration 18 gram of water is added to 1 mole of gas [D] on warming with mercuric sulphate and dilute acid at 333 K to form compound [E]. The IUPAC name of compound [ E ] is :

A
Butan-2-ol
B
But-2-yne
C
Butan-2-one
D
Butan-1-al
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