1
JEE Main 2025 (Online) 2nd April Morning Shift
MCQ (Single Correct Answer)
+4
-1

Let $B_1$ be the magnitude of magnetic field at center of a circular coil of radius $R$ carrying current I. Let $\mathrm{B}_2$ be the magnitude of magnetic field at an axial distance ' $x$ ' from the center. For $x: \mathrm{R}=3: 4, \frac{\mathrm{~B}_2}{\mathrm{~B}_1}$ is :

A
$64: 125$
B
$25: 16$
C
$4: 5$
D
$16: 25$
2
JEE Main 2025 (Online) 2nd April Morning Shift
MCQ (Single Correct Answer)
+4
-1

A light wave is propagating with plane wave fronts of the type $x+y+z=$ constant. Th angle made by the direction of wave propagation with the $x$-axis is :

A
$\cos ^{-1}(2 / 3)$
B
$\cos ^{-1}\left(\frac{1}{\sqrt{3}}\right)$
C
$\cos ^{-1}\left(\frac{1}{3}\right)$
D
$\cos ^{-1}\left(\sqrt{\frac{2}{3}}\right)$
3
JEE Main 2025 (Online) 2nd April Morning Shift
MCQ (Single Correct Answer)
+4
-1

Match List I with List II.

List - I List - II
(A) Coefficient of viscosity (I) $\left[\mathrm{ML}^0 \mathrm{~T}^{-3}\right]$
(B) Intensity of wave (II) $\left[\mathrm{ML}^{-2} \mathrm{~T}^{-2}\right]$
(C) Pressure gradient (III) $\left[\mathrm{M}^{-1} \mathrm{LT}^2\right]$
(D) Compressibility (IV) $\left[\mathrm{ML}^{-1} \mathrm{~T}^{-1}\right]$

Choose the correct answer from the options given below:

A
(A)-(II), (B)-(III), (C)-(IV), (D)-(I)
B
(A)-(IV), (B)-(II), (C)-(I), (D)-(III)
C
(A)-(IV), (B)-(I), (C)-(II), (D)-(III)
D
(A)-(I), (B)-(IV), (C)-(III), (D)-(II)
4
JEE Main 2025 (Online) 2nd April Morning Shift
MCQ (Single Correct Answer)
+4
-1

A particle is subjected to two simple harmonic motions as : $$ x_1=\sqrt{7} \sin 5 \mathrm{tcm} $$ and $x_2=2 \sqrt{7} \sin \left(5 t+\frac{\pi}{3}\right) \mathrm{cm}$ where $x$ is displacement and $t$ is time in seconds. The maximum acceleration of the particle is $x \times 10^{-2} \mathrm{~ms}^{-2}$. The value of $x$ is :

A
$5 \sqrt{7}$
B
125
C
$25 \sqrt{7}$
D
175
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